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3 years ago

A cube has the volume of 216 in3 determine the area of on face of the cube

Mathematics

1 answer:

lara31 [8.8K]3 years ago

7 0

Answer:

36 inches squared

Step-by-step explanation:

volume is found by length x width x height on a cube they are all the same

so its x³ = 216

∛x³ = ∛216 get cube root of both sides

x = 6 (∛x³ cube root of x cubed is just x)

face is sides x sides so thats 6 x 6 = 36

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4 years ago

The perimeter of a rectangular garden is

olganol [36]

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3 years ago

What is the solution of StartRoot x squared + 49 EndRoot = x + 5?

Natasha2012 [34]

$x=\frac{12}{5}$ or x= twelve-fifths

Option A is correct.

Step-by-step explanation:

We need to find the solution of:

$\sqrt{x^2+49}=x+5$

Solving:

Taking square on both sides:

$(\sqrt{x^2+49})^2=(x+5)^2\\x^2+49=x^2+2(x)(5)+25\\Simplifying:\\x^2+49-x^2-10x-25=0\\-10x+24=0\\-10x=-24\\x=\frac{-24}{-10}\\ x=\frac{24}{10}\\x=\frac{12}{5}$

Verifying the solution by putting x = 12/5 in the given equation, we get true result.

So, $x=\frac{12}{5}$ or x= twelve-fifths

Option A is correct.

Keywords: Solving Square root Equations

Learn more about Solving Square root Equations at:

#learnwithBrainly

5 0

4 years ago

Read 2 more answers

Five more than three times a number is twenty-six.

Rzqust [24]

Answer:

Step-by-step explanation:

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3 years ago

Solve: (-5/6) × (9/20) + (-5/6) × 7/25 = ?

jonny [76]

$\bf \underline{★ How \:to\: do -} \\$

Here, we are given with four fractions to multiply two of them and to add two of them. If we add them directly by taking the LCM and adding them is not a similar way. We can clearly observe that in those four fractions, we have two fractions as common i.e, we have two fractions as same. If we have two fractions or numbers as same, we can solve the sum by an other concept called as distributive property. In this property, we multiply the common fraction with the sum of other two fractions. This concept can also be done with fractions as well as integers. So, let's solve!!

$\:$

$\bf \underline{➤ Solution-} \\$

${\tt \leadsto \dfrac{(-5)}{6} \times \dfrac{9}{20} + \dfrac{(-5)}{6} + \dfrac{7}{25}}$

Group the non-common fractions in bracket.

${\tt \leadsto \dfrac{(-5)}{6} \times \bigg( \dfrac{9}{20} + \dfrac{7}{25} \bigg)}$

First we should solve the numbers in bracket.

LCM of 20 and 25 is 100.

${\tt \leadsto \dfrac{(-5)}{6} \times \bigg( \dfrac{9 \times 5}{20 \times 5} + \dfrac{7 \times 4}{25 \times 4} \bigg)}$

Multiply the numerators and denominators in the bracket.

${\tt \leadsto \dfrac{(-5)}{6} \times \bigg( \dfrac{45}{100} + \dfrac{28}{100} \bigg)}$

Now, write both numerators in bracket with a common denominator.

${\tt \leadsto \dfrac{(-5)}{6} \times \bigg( \dfrac{45 + 28}{100} \bigg)}$

Now, add the numerators in bracket.

${\tt \leadsto \dfrac{(-5)}{6} \times \bigg( \dfrac{73}{100} \bigg)}$

Write the numerator and denominator in lowest form by cancellation method.

${\tt \leadsto \dfrac{\cancel{(-5)} \times 73}{6 \times \cancel{100}} = \dfrac{(-1) \times 73}{6 \times 20}}$

Now, multiply the numerators and denominators.

${\tt \leadsto \dfrac{(-73)}{120}}$

$\:$

${\red{\underline{\boxed{\bf So, \: the \: answer \: obtained \: is \: \: \dfrac{(-73)}{120}}}}}$

3 0

3 years ago