I'll do a similar problem, and I challenge you to do this using similar techniques!
If John works for 15$ a hour with his friends rather than working for 20$ an hour for 50 hours a month, what's the monthly opportunity cost?
John would make 20*50=1000 dollars a month at the second option as he makes 20$ an hour 50 times. Next, if he works with his friends, he makes 15*50=750 dollars as he works 50 hours for 15 dollars an hour, or adds 15 50 times.
His opportunity cost would be <highest money>-<lowest money>=1000-750=250 dollars a month. Good luck on this question, and feel free to ask further questions!
Answer:
1/2 o 50%
Step-by-step explanation:
debemos partir de la presuncion que un bebe puede ser niño o niña uinicamente, o sea la P(niño) + P(niña) = 1
no existen los bebes que son niños y niñas al mismo tiempo, eso quiere decir que es una opcion o la otra
P(niña) = 1 - P(niño) = 1 - 1/2 = 1/2 = 0.5 = 50%
Discussion
The discriminate is b^2 - 4*a*c
The general equation for a quadratic is ax^2 + bx + c
In this equation's case
a = 1
b= -5
c = - 3
Solve
(-5)^2 - 4*(1)*(-3)
25 - (-12)
25 + 12
37
Note
Since the discriminate is > 0, the roots are real and different. The roots do exist and there are 2 of them.
Answer:
a. 2.2 m
b. 8 m
Step-by-step explanation:
4) a. Sin 32 = x/4
= (sin 32)(4) = x
b. Cos 65 = 4.5/x
x = 4.5/Cos 65
