3.√(27x^9) = (27x^9)^(1/3) = 3x^3
A rhombus diagonals form right angles. The diagonals also cut in half the angles
use cosine: cos38 =
a = 20cos38
a=15.8
Any fraction that can be simplified to 1/4 would work. I don't have a model to shade, but I can give you some examples. 2/8, 3/12, 4/16, 5/20... I hope this helps!
The recursive formula of the geometric sequence is given by option D; an = (1) × (5)^(n - 1) for n ≥ 1
<h3>How to determine recursive formula of a geometric sequence?</h3>
Given: 1, 5, 25, 125, 625, ...
= 5
an = a × r^(n - 1)
= 1 × 5^(n - 1)
an = (1) × (5)^(n - 1) for n ≥ 1
Learn more about recursive formula of geometric sequence:
brainly.com/question/10802330
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Answer:
12
Step-by-step explanation:
Well the way i said it was
-
42-30= 12
altho i not very sure