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elena-14-01-66 [18.8K]
4 years ago
5

A scale drawing of a playground is shown below.

Mathematics
1 answer:
kolezko [41]4 years ago
7 0
Hm... I think 440 Square feet..?
You might be interested in
Evaluate (-27)^-4/3 ((-27 to the power of -4/3))
masha68 [24]

Answer:

-1/81

Step-by-step explanation:

-27^-4/3

cbrt(-27^-4)

cbrt(-1/531441)

-1/81

5 0
3 years ago
Read 2 more answers
1. Thom has a scale model of his car. The
MariettaO [177]

x =\frac{4}{3}inch is the size in wheels on the scale model .

<u>Step-by-step explanation:</u>

Correct Question : Tom has a scale model of his car. The scale factor is 1 : 12. If the actual car has 16-inch wheels, what size are the wheels on the scale model?

We have , The scale factor is 1 : 12. We need to find If the actual car has 16-inch wheels, what size are the wheels on the scale model .Let's find out:

Ratio of size of wheels to actual size of wheels is 1:12 , but actual car has 16-inch wheels So ,

⇒ \frac{1}{12}  = \frac{x}{16}                 { x is size of wheel in scale model }

⇒ \frac{1(16)}{12}  = \frac{x}{16}(16)

⇒ x =\frac{16}{12}

⇒ x =\frac{4}{3}inch

Therefore , x =\frac{4}{3}inch is the size in wheels on the scale model .

5 0
4 years ago
Which of the following points could be the initial point of vector v if it has a magnitude of 10 an the terminal point (-1,5)?
Eddi Din [679]
Let the initial point of the vector be (x,y). Then the magnitude of the vector v can be written as:

|v|= \sqrt{ (-1-x)^{2} + (5-y)^{2} }

The magnitude of vecor v is given to be 10. So we can write:

10= \sqrt{ (-1-x)^{2} + (5-y)^{2} } \\ \\ 100=(-1-x)^{2} + (5-y)^{2}

Now from the given options, we have to check which one satisfies the above equation. That point will be the initial point of the vector. 

The point in option d, satisfies the equation.

100=(-1+7)^{2} +(5+3)^{2}  \\  \\ &#10;100=36+64 \\  \\ &#10;100=100

Thus, the answer to this question is option D
7 0
3 years ago
Jasmine had a carrot cake with cream cheese frosting for her birthday .she and her friend each ate 1/4 of the cake and jasmine's
zloy xaker [14]
Hey there!

To solve this problem, you first would need to solve for how much of the cake is left after Jasmine, her friend, and Jasmine's brother got their slices. Then, you would need to split the remaining amount in half to get the answer of what each parent ate. We would need to make all of the denominators the same, so let's make all of the fractions out of 12, a common denominator of 3 and 4. 

\frac{12}{12} - \frac{1}{4} - \frac{1}{4} - \frac{1}{3}
\frac{12}{12} - \frac{3}{12} - \frac{3}{12} - \frac{4}{12}
\frac{12}{12} - \frac{10}{12} = \frac{2}{12}

It can then be concluded that each parent ate \frac{1}{12} of the cake, since there was \frac{2}{12} remaining. 

You can check this answer by adding up all of the parts we used in this problem:

\frac{3}{12} + \frac{3}{12} + \frac{4}{12} +  \frac{1}{12} +  \frac{1}{12} = \frac{12}{12}

Hope this helped you out! :-)
3 0
3 years ago
Find the complementary angles of the following.
vovikov84 [41]

Answer:

1. 87

A77

B24

C93

D47

E 31

F 48

2. 160

A10

B20

C30

D40

E 50

F 60

3. 68

A851

B295

C302

D574

E 112

F 638

4. 174

A3

B4

C5

D 6

E 7

F 8

5. a

A180-a

B180/2

C 179*a

D 179+a

E 60

F pi

Find the complementary angles of the following.

6. 53

A90

B32

C 25

D 45

E 18

F 37

7. 12

A46

B78

C98

D31

E 52

F 64

8. 73.5

A16.5

B34.2

C29.4

D17.7

E 57.9

F 11.3

9. 23.7

A66.3

B70.1

C42.5

D83.9

E 54.8

F 36.2

10. a

A90/a

Ba-90

Ca/2

D90-a

E 90-2

F a^2

Two of the angles are listed. Find the measure of the third angle in each triangle. Similar to example 6

11. 16,42

A256

B421

C107

D510

E 122

F 329

12. 90, 30

A23

B42

C47

D60

E 71

F 89

13. 43, 118

A12

B34

C19

D57

E 11

F 27

14. 60, 60

A15

B90

C29

D60

E 30

F 45

15. 14, 123

A73

B25

C38

D19

E 43

F 13

16. 68, 86

A45

B56

C26

D19

E 32

F 82

17. 55, 77

A18

B37

C62

D57

E 20

F 48

18. a, (a + 80)

A100 - 2a

B112 - 7a

C182 - 2a

D254 - 5a

E 311 - 3a

F 302 - 1a

19. x, (x + 20)

A189 - 7x

B167 - 1x

C114 - 5x

D160 - 2x

E 124 - 2x

F 142 - 1x

20. m, 2m

A172 - 2m

B187 - 7m

C124 - 4m

D143 - 1m

E 164 - 9m

F 180 - 3m

1. C

2. B

3. E

4. D

5. D

6. F

7. B

8. A

9. A

10. B

11. D

12. A

13. D

14. B

15. A

16. C

17. F

18. A

19. D

20. F

Step-by-step explanation:

6 0
3 years ago
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