Fo two disk i problem 3 what is the ratio of linear accerlation of a point on the rim of disk a

According to astronomers, what is a "light year" answer key

liberstina [14]

A light-year is defined as the distance the light can cover in one year.

The light travels at speed of $c=3 \cdot 10^8 m/s$ , and one year converted into seconds is
$1 y = 365 \frac{d}{y} \cdot 24 \frac{h}{d} \cdot 60 \frac{m}{h} \cdot 60 \frac{s}{m}=3.15 \cdot 10^7 s$

So the distance covered by the light in one year is
$S=vt =(3 \cdot 10^8 m/s)(3.15 \cdot 10^7 s)=9.45 \cdot 10^{15} m$
And this is the distance that corresponds to one light-year.

3 0

3 years ago

X²+y²-6x+14y-1=0<br> and please show your work so I can learn

Eva8 [605]

Hello there,

I hope you and your family are staying safe and healthy during this winter season.

$x^2 + y^2 -6x+14y-1=0$

We need to use the Quadratic Formula*

$x =\frac{-b+\sqrt{b^2}-4ac }{2a}$ , $\frac{-b-\sqrt{b^2} -4ac }{2a}$

Thus, given the problem:

$a = 1, b=-6, c=y^2+14y-1$

So now we just need to plug them in the Quadratic Formula*

$x=\frac{6+2\sqrt{(-6)^2-4(y^2+14y-1)} }{2}$ , $x=\frac{6-\sqrt{(-6)^2-4(y^2+14y-1)} }{2}$

As you can see, it is a mess right now. Therefore, we need to simplify it

$x=\frac{6+2\sqrt{10-y^2-14y} }{2}$ , $x = \frac{6-2\sqrt{10-y^2-14y} }{2}$

Now that's get us to the final solution:

$x=3+\sqrt{10-y^2-14y}$ , $x=3-\sqrt{10-y^2-14y}$

It is my pleasure to help students like you! If you have additional questions, please let me know.

Take care!

~Garebear

3 0

2 years ago

The graph of a linear

Gwar [14]

Answer:

Where is the graph?

Step-by-step explanation:

8 0

2 years ago

If 4 bags of corn can feed a herd of cows for 6 days, how many bags will feed the herd for 9 days ?

VARVARA [1.3K]

Well, if 6/4 equals 1.5 --

Then 1.5*5, (which is the next quantity of days before it hits 9) equals 7.5.

Hope this helps.

7 0

2 years ago

You can walk 3 miles per hour, jog 5 miles per hour, or run 10 miles per hour. You go a full hour before changing pace. At the e

Studentka2010 [4]

Answer:

b. How many ways arc there to go 12 miles?

≡ p(12) = 25

c. How many ways arc there to go 20 miles?

≡ p(20) = 131

d. How many ways arc there to go 22 miles?

≡p(22) 199

Step-by-step explanation:

a) supposed you walked for the first hour. Then you would have travelled 3 miles. if you jogged you would have covered 5miles and if you run you would have covered 10miles. now you have to decide how to run the rest miles from the n miles.

Thus, the number of ways one can cover n miles will be given by the recurrence relation

p(n) = p( n-3) + p( n-5) + p( n - 10)

now to solve the rest of the question, let us make a table which provides the number of ways for n = 1 to 22.

check the attachment for the table

b. How many ways arc there to go 12 miles?

≡ p(12) = 25

c. How many ways arc there to go 20 miles?

≡ p(20) = 131

d. How many ways arc there to go 22 miles?

≡p(22) 199

8 0

3 years ago