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3 years ago

ANSWER pls........................

Mathematics

1 answer:

Anettt [7]3 years ago

6 0

Answer:

Step-by-step explanation:

Ok so first the chicken. 12.36 x 2= 24.72

Broccoli. 1.98 divides by 2= 0.99

Milk. 3.49, easy.

so add them up and you get 29.20, remember, she recieves .80 back, so she paid 30 because 29.20 + .80 = 30 Hope this helps! Have a good day! :)

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Given f(x)=x^3+2x+k.<br> and x+1 is a factor of f(x), then what is the value of k?

Ludmilka [50]

Answer:

k = 3.

Step-by-step explanation:

By the Factor Theorem. if x+a is a factor of f(x) then f(-a) = 0.

Here we use f(-1):

f(-1) = (-1)^3 + 2(-1) + k = 0

-1 - 2 + k = 0

k = 3.

4 0

3 years ago

A manufacturer is running an experiment using the standard (control) infant formula, and two new formulas, A and B. The goal is

bulgar [2K]

Answer:

H0: the mean IGA score is the same for all three formulas. 

Ha: the mean IGA score is not the same for all three formulas.

The Group of answer choices are as below:

H0: the mean IGA score is the same for all three formulas. 

Ha: the mean IGA score is not the same for all three formulas.

H0: the mean IGA score is the same for all three formulas. 

Ha: the mean IGA score is higher for at least one of the two treatment groups than the control group

H0: the mean IGA score is the same for all three formulas. 

Ha: the mean IGA score is higher for both treatment groups A and B than the control group.

D. No answer text provided.

Explanation:

Given that a manufacturer is running an experiment using the standard (control) infant formula, and two new formulas, A and B to boost the immune system in infants.

The variable that is measured is Total IGA (in mg per dl) score.

We have to state the hypotheses for one-way ANOVA F test to test if the mean IGA score is the same for all three formulas.

In null hypothesis H0, the mean of all groups are equal and in alternative hypothesis, Ha, the mean of the groups are not the same.

Therefore, the hypothesis tested by the one-way ANOVA F test are:

H0: the mean IGA score is the same for all three formulas.

Ha: the mean IGA score is not the same for all three formulas.

5 0

3 years ago

The endpoints of PQ are P(2, 0) and Q (4, 2). Find the coordinates of midpoint PQ.

lawyer [7]

Answer:

Step-by-step explanation:

Parameterize the ellipse as (acos∙,bsin∙). Take points P:=(acosp,bsinp) and Q:=(acosq,bsinq) on the ellipse, with midpoint M:=(P+Q)/2.

If |PQ|=2k, then

a2(cosp−cosq)2+b2(sinp−sinq)2=4k2

The coordinates of M are

xy==a2(cosp+cosq)b2(sinp+sinq)

4 0

4 years ago

There are 25 trees on the Jackson’s property. Twenty percent of the trees are oak trees. Which equation can be used to find the

Luba_88 [7]

It would be 35 is the best answer

6 0

4 years ago

What is 11/12 minus 3/8

Mrac [35]

Answer: $\frac{13}{24}$

Step-by-step explanation: 11/12 - 3/8

1. First, we will find a common denomenator. It needs to be the least common factor, or the answer will not be in its simplist form. Let's take a look at the multiples of 12 and 8.

12: 12, 24, 36, 48, 60, 72, 84, 96

8: 8, 16, 24, 32, 40, 48, 56, 64, 72

2. Next, we will choose the smallest common multiple. That would be 24.

3. Now, we will work this out.

11/12 = 22/24

3/8 = 9/24

4. Subtract.

22/24 - 9/24

= 13/24

= $\frac{13}{24}$

I found the denomenators by multiplying.

Hope this answer helped!

8 0

3 years ago