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Ede4ka [16]
3 years ago
12

The two triangles are similar. What is the value of x? Enter your answer in the box. x = Two right triangles, one smaller than t

he other, back to back, so that their right angles form a straight angle. The two acute angles along the straight angle are congruent to each other. The overlapping part of the legs is labeled 20. The part of the overlapping side that extends above the smaller triangle is labeled 8. The leg of the smaller triangle that is a ray of the straight angle is labeled 3 x. The leg of the larger angle that is a ray of the straight angle is labeled 4 x plus 2.

Mathematics
2 answers:
11111nata11111 [884]3 years ago
8 0

Free right answer sample, get your free right answer sample over here.

(psst it's 10)

inysia [295]3 years ago
4 0
<span>x = 4
   Given the description of the triangles, you have 2 similar right triangles. The smaller triangle has a height of 20 and a base of 3x, while the larger has a height of (20+8) = 28 and a base of 4x + 2. We wish to determine the value of x. Since the triangles are similar, the ratio of corresponding sides will be a constant. So:
 20/28 = (3x)/(4x+2)
 (4x+2)20/28 = (3x)
 (20/28)*4x+(20/28)*2 = (3x)
 (80/28)*x+(40/28) = (3x)
 (20/7)*x + 4/7 = 3x
 4/7 = 3x - (20/7)*x
 4/7 = (21/7)x - (20/7)*x
 4/7 = x/7
 4 = x
   So the value of x is 4.</span>
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A rectangle is 5 cm wider than twice its length. If the perimeter of the rectangle is 70 cm, then what is the area?
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Step-by-step explanation:

The dimensions of the rectangle are two unknowns: The length "l" and the width "w"

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We also know that the length is 5cm more than twice the width. l = 2*w + 5

These two equations gives us a system of linear equations.

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We can use substitution to replace the "l" in the first equation with 2*w + 5

P = 2*(2*w + 5) + 2*w

P = 4*w + 10 + 2*w

P = 6*w + 10

we know the perimeter is 70

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Now that we know the width, we can find the length by substituting 10 for "w" in the second equation.

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l = 25

the dimentions of the rectangle are 25cm x 10 cm

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3 years ago
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