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3 years ago

What is the answer to this problem? 96+56+75+25*54+95(58)-95= ?

Mathematics

2 answers:

Yuliya22 [10]3 years ago

5 0

Hello again!~

The answer to this question would be:

6992

Have an amazing day!~

brilliants [131]3 years ago

3 0

The answer to this problem would be 6992.

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A 70 cm long stick is cut into two parts in such a way that the longer part is 20 cm longer than the shorter part. How long is e

Pachacha [2.7K]

Answer:

The longer part is 45 cm long and the shorter part is 25 cm long.

Step-by-step explanation:

Given:

A 70 cm long stick is cut into two parts in such a way that the longer part is 20 cm longer than the shorter part.

Now, to find the length of each part of the stick.

Let the shorter part be $x.$

So, the longer part is $x+20.$

Total length of the stick = 70 cm.

Now, to get the length of each part we solve an equation:

$(x)+(x+20)=70\\\\x+x+20=70\\\\2x+20=70\\\\Subtracting\ both\ sides\ by\ 20\ we\ get:\\\\2x=50\\\\Dividing\ both\ sides\ by\ 2\ we\ get:\\\\x=25.$

The length of the shorter part is 25 cm.

Now, substituting the value of $x$ :

$x+20\\\\=25+20\\\\=45\ cm.$

The length of longer part is 45 cm.

Therefore, the longer part is 45 cm long and the shorter part is 25 cm long.

6 0

3 years ago

What times what equals seventy five

Novay_Z [31]

1*75=75
3*25=75
and
5*15=75

6 0

3 years ago

The temperature function (in degrees Fahrenheit) in a three dimensional space is given by T(x, y, z) = 3x + 6y - 6z + 1. A bee i

madam [21]

You're looking for the extreme values of $T(x,y,z)=3x+6y-6z+1$ subject to $x^2+y^2+z^2=9$ . The Lagrangian is

$L(x,y,z,\lambda)=3x+6y-6z+1+\lambda(x^2+y^2+z^2-9)$

with critical wherever the partial derivatives vanish:

$L_x=3+2\lambda x=0\implies x=-\dfrac3{2\lambda}$

$L_y=6+2\lambda y=0\implies y=-\dfrac3\lambda$

$L_z=-6+2\lambda z=0\implies z=\dfrac3\lambda$

$L_\lambda=x^2+y^2+z^2-9=0$

Substituting the first three solutions into the last equation gives

$\dfrac9{4\lambda^2}+\dfrac9{\lambda^2}+\dfrac9{\lambda^2}=9$

$\implies\lambda=\pm\dfrac32$

$\implies x=1,y=2,z=-2\text{ or }x=-1,y=-2,z=2$

At these points, we have

$T(1,2,-2)=28$

$T(-1,-2,2)=-26$

so the highest temperature the bee can experience is 28º F at the point (1, 2, -2), and the lowest is -26º F at the point (-1, -2, 2).

6 0

3 years ago

Select the question that is different from the other three.

dlinn [17]

yup and your going to jail :)

3 0

3 years ago

M is the midpoint of LN. L has coordinates (-3,-1) and M has coordinates (0,1). Find N coordinates.

miskamm [114]

To get the coordinates, we would use the midpoint formula (google it)

(X1-X2/2 , Y1+Y2/2)

(-3+0/2 , -1+1/2)

N: (-3/2,0)

8 0

3 years ago