Question

Which one of the following substances would be the most soluble in CCl4?

Answer 1

Answer: Option (d) is the correct answer.

Explanation:

Carbon tetrachloride $(CCl_{4})$ is a non-polar solvent. Whereas out of the given options, $Na_{2}SO_{4}$, $H_{2}O$, $CH_{3}CH_{2}CH_{2}CH_{2}OH$, and HI are all polar molecules.

On the other hand, only $C_{4}H_{10}$ is non-polar molecule.

Also it is known that like dissolves like.

So, being non-polar $CCl_{4}$ will dissolve the give alkane, $C_{4}H_{10}$.