Answer:
Explanation:
Examples of applied chemistry include creation of the variety of laundry detergents on the market and development of oil refineries.
Answer : The molecular weight of a gas is, 128.9 g/mole
Explanation : Given,
Density of a gas = 5.75 g/L
First we have to calculate the moles of gas.
At STP,
As, 22.4 liter volume of gas present in 1 mole of gas
So, 1 liter volume of gas present in mole of gas
Now we have to calculate the molecular weight of a gas.
Formula used :
Now put all the given values in this formula, we get the molecular weight of a gas.
Therefore, the molecular weight of a gas is, 128.9 g/mole
Answer:
Explanation:
There are three types of interactions involved between the particles when solution are formed.
1 : Solute - solute interaction:
2 : Solute - solvent interaction:
3 : Solvent - solvent interaction:
1 : Solute - solute interaction:
It is the inter-molecular attraction between the solute particles.
2 : Solute - solvent interaction:
It involve the inter-molecular attraction between solvent and solute particles.
3 : Solvent - solvent interaction:
It involve the intermolecular attraction between solvent particles.
Solutions are formed if the intermolecular attraction between solute particles are similar to the attraction between solvent particles.
Exothermic process:
The process will exothermic when solute solvent bonds are formed with the release of energy and energy required to brake the solute-solute particles and solvent solvent particles are less.
Endothermic process:
The process will be endothermic when energy required to break the solute-solute particles and solvent solvent particles are higher than energy released when solute solvent bonds are formed .
Answer:
100.8 °C
Explanation:
The Clausius-clapeyron equation is:
-Δ
Where 'ΔHvap' is the enthalpy of vaporization; 'R' is the molar gas constant (8.314 j/mol); 'T1' is the temperature at the pressure 'P1' and 'T2' is the temperature at the pressure 'P2'
Isolating for T2 gives:
(sorry for 'deltaHvap' I can not input symbols into equations)
thus T2=100.8 °C