The possible different outcomes are: c. 6 outcomes.
you can only count "e" once because even though it is in the bag twice, drawing it a second time would be the same outcame.
hope this help
Answer:
x = 32 y = 16 z = 64
Step-by-step explanation:
x is the 1st number
y is the 2nd number
z is the 3rd number
The first number is twice the second number so
x = 2 y
The third number is twice the first number.
z = 2 x
Their sum is 112
x + y + z = 112
Plus in what we know:
x + y + z = 112
2 y + y + 2x = 112
3y + 2x = 112 Let's solve for y and subtract 2x from each side
3y = 112 - 2x Divide both sides by 3
y = 
Now plug our answer back in to solve for x.
x = 2y
x = 2 (
)
x = (224 - 4x) / 3 Multiply each side by 3.
3x = 224 - 4x Add 4x to each side
3x + 4x = 224
7x = 224 Divide each side by 7
7x / 7 = 224 / 7
x = 32
Now we can solve for z.
z = 2x
z = 2 ( 32 )
z = 64
Now we can solve for the numerical value of y.
x + y + z = 112
32 + y + 64 = 112
96 + y = 112 Subtract 96 from each side.
y = 112 - 96
y = 16
A coefficient is a number multiplied by a variable.
In this case, our variable is a.
The coefficient is 12.
(PS: The +5 that isn't being multiplied by a variable is called a constant)
I think the Caldwell family (tbh I don’t know ♀️)
The vertical asymptote of the function that are illustrated in the calculus and the function y = 3cot(1/2x) - 4 will be:
B. x = 0
C. x = +-2π
<h3>How to illustrate the information?</h3>
It should be noted that the function that's given from the information illustrated is given as:
y = 3 for (x/2) - 4
It should be noted that there is no phase shift and the period is 2π.
It should be noted that the vertical asymptote will be x = 3πn where no is represented as the integer at n = 0, 1, and -1.
Therefore, the vertical asymptote of the function that are illustrated in the calculus and the function y = 3cot(1/2x) - 4 will be x = 0 and x = +2π.
Learn more about calculus on:
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