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BlackZzzverrR [31]
3 years ago
11

“76 is 60% of what?” Help!

Mathematics
1 answer:
kipiarov [429]3 years ago
5 0

126.67

      Hope this helps!

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Grades in large classes are sometimes approximately Normally distributed—a fact that serves as the justification for "grading on
QveST [7]

Answer:

Grade A: Z \geq 1

Grade B: 0 \leq Z < 1

Grade C: -1 \leq Z < 0

Grade D: Z < -1

Step-by-step explanation:

Problems of normally distributed samples can be solved using the Z score table.

The Z score of a measure represents how many standard deviations it is above or below the mean of all the measures.

Each Z score has a pvalue. This represents the percentile of the measure.

In this problem, we have that:

The upper 16% of the class get A grades. The upper 16% has a pvalue of at least 100% = 16% = 84% = 0.84. This is Z \geq 1.

The middle 34% of the class get B grades. The middle 34% has a pvalue of at least 84%-35% = 50% = 0.5 and at most 0.84. This is 0\leqZ < 1.

Those between a pvalue of 0.5-0.34 = 0.16 and 0.5 get get grade C. Z = -1 has a pvalue of 0.16. So a grade C is in the interval -1 \leq Z < 0.

Those with Z lesser than -1 get grades D and F

6 0
3 years ago
NEED HELP ASAP! GIVING BRAINLIEST TO WHOEVER ACTUALLY ANSWERS WITH HOW TO DO THE PROBLEM AS WELL. THANK YOU &lt;3
liq [111]

Answer:

2.53800027 ^9

Step-by-step explanation:

the product of both numbers is this.

just add both of them together. If im wrong, i will tell you another answer.

6 0
3 years ago
10 points will give brainliest
Gre4nikov [31]

Answer:

A. 9/2 × 3/8

Step-by-step explanation:

______________

7 0
3 years ago
Read 2 more answers
What does square root x^16 equal?
In-s [12.5K]
Sqrt(x^16) is x^8.
As you can see, x^8 * x^8 = x*x*x*x*x*x*x*x * x*x*x*x*x*x*x*x which equals x^16
I don't know why Cortesalondra28 deleted my answer to the question and sayid it was wrong..
8 0
3 years ago
Read 2 more answers
One number is 2 more than 3 times another. Their sum is 22. Find the numbers.
ivolga24 [154]
Make a system of equations.

\sf~x=3y+2
\sf~x+y=22

Re-arrange the 2nd equation:

\sf~x+y=22

Subtract y to both sides:

\sf~x=-y+22

Plug in -y + 22 for 'x' in the first equation.

\sf~x=3y+2

\sf~-y+22=3y+2

Subtract 3y to both sides:

\sf~-4y+22=2

Subtract 22 to both sides:

\sf~-4y=-20

Divide -4 to both sides:

\sf~y=\boxed{\sf5}

Plug this into any of the two equations to find 'x':

\sf~x+y=22

\sf~x+5=22

Subtract 5 to both sides:

\sf~x=\boxed{\sf17}

So one of the numbers is 5 and one of them is 17.
6 0
3 years ago
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