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3 years ago

How to find x and y (the answer is x=25,y=20 but i couldn't get the answer

Mathematics

1 answer:

Yakvenalex [24]3 years ago

7 0

How are you going to ask a question and answer it yourself w t f

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Joe's Junkyard sold 122 pieces of desk art from recycled materials at $7.50 each in its test market last year. It has 35 additio

Sidana [21]

157 x 7.50 = $1,177.50

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3 years ago

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MgSO4(aq) + 2 NH4OH(aq) → Mg(OH)2(s) + (NH4)2SO4(aq)

alexira [117]

It's not clear what did you mean with this equation. But I guess you need the balanced net ionic equation, as I've seen that problem before. So here it is: $Mg^{2+} +2OH -\ \textgreater \ Mg(OH)_{2}$

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3 years ago

2.) Fill in the blank.

Montano1993 [528]

Answer:

E.) 1

Step-by-step explanation:

Firstly we will solve for L.H.S.

L.H.S. = $Csc^2\theta$

Since we know that $Csc^2\theta$ is the inverse of $Sin^2\theta$ .

So we can say that;

$csc^2\theta=\frac{1}{sin^2\theta}$

Now For R.H.S.

$Cot^2\theta+1$

Since we can rewrite $cot^2\theta$ as $\frac{cos^2\theta}{sin^2\theta}$ .

Now we can say that the R.H.S. is;

$\frac{cos^2\theta}{sin^2\theta}+1$

Now we add the fraction and get;

$\frac{cos^2\theta+sin^2\theta}{sin^2\theta}$

Now according to trigonometric identity;

$cos^2\theta+sin^2\theta=1$

So, $\frac{cos^2\theta+sin^2\theta}{sin^2\theta}=\frac{1}{sin^2\theta}$

Here,

$csc^2\theta=\frac{1}{sin^2\theta}$ and $Cot^2\theta+1$ = $\frac{1}{sin^2\theta}$

L.H.S. = R.H.S.

Hence $csc^2\theta=cot^2\theta+1$

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2 years ago

Brice has 400 toy cars. Of the toy cars, 15% are red, 40% are green, and the rest are multicolor.

mixas84 [53]

Answer:

180

Step-by-step explanation:

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3 years ago

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(9x−2.25)=(1.6+9x) help

mel-nik [20]

Begin solving like you normally would. Add 2.25 to both sides and subtract 9x from both sides to try getting all x values on one side. However, you will find that after subtracting 9x from both sides, all x values go away, and you end with -2.25=1.6. This is not true (-2.25 is not 1.6), so the answer is no solution. There is no value of x which satisfies that equation.

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3 years ago