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Oksana_A [137]
3 years ago
8

Inverse of 3/x^2+2x

Mathematics
2 answers:
Anit [1.1K]3 years ago
8 0
(Root symbol) and under that 3x. And then outside of the root symbol -2x
viva [34]3 years ago
5 0
3x out side of the root symbol is -2x
You might be interested in
Part A: describe how you can decompose this shape into triangles. (2 points) Part B: what would be the area of each triangle? (5
Kipish [7]

Answer:

Part A: Describe how you can decompose this shape into triangles: If you draw a line from each vertex to the vertex at the opposite side of the hexagon, you will form 6 triangles.

Part B: What would be the area of each triangle: 62.4

​

Part C: Using your answers above, determine the area of the table's surface: 374 .4

Step-by-step explanation:

Part A: Describe how you can decompose this shape into triangles: If you draw a line from each vertex to the vertex at the opposite side of the hexagon, you will form 6 triangles.

Part B: What would be the area of each triangle: bxh /2

12 x 10.4 /2

​

Part C: Using your answers above, determine the area of the table's surface:  374.4

5 0
2 years ago
Find the truth value of (p ^ q) v r. (Make a truth table.)
alexgriva [62]

Answer:

p: (-4)2 > 0

q: An isosceles triangle has two congruent sides.

r: Two angles, whose measure have a sum of 90, are supplements.​

Step-by-step explanation:

p: (-4)2 > 0

q: An isosceles triangle has two congruent sides.

r: Two angles, whose measure have a sum of 90, are supplements.​

4 0
3 years ago
Louis wants to carpet the rectangular floor of his basement. The basement has a area of 768 square feet. The width of the baseme
pentagon [3]
Area=width*length. Let width=x ft, then length=3x ft, given the information in the problem. The area of basement=x*3x=768, 3x^2=768, x^2=256, x=16. The width is 16 feet. Therefore, length=3x=3*16=48 feet.
5 0
3 years ago
Image attachment below, Algebra 1 stuff
chubhunter [2.5K]
I know you didn't want an explanation, but I'll give you one anyway.
So, for a function, when you have f(5) = , then you'll put that 5 in for all of the x's in the function. 

The first batch of problems gave you the equation f(x) = \frac{x}{2} + 3. Now, plug in the numbers given for s and solve.

1. f(5) = <span>\frac{x}{2} + 3   Plug in 5 for x
</span>         = \frac{5}{2} + 3   Make three into a fraction over 2
         = \frac{5}{2} + <span>\frac{6}{2}   Add
         = </span><span><span>\frac{11}{2}

</span>2. f(-4) = </span><span>\frac{x}{2} + 3   Plug in -4 for x
           = </span><span>\frac{-4}{2} + 3   Divide -4 by 2
           = -2 + 3   Add
           = 1

For the next set, you have g(x) = x</span>² + 1.

3. Let's split this up. Solve the first equation, then the second, and then put         the answers together to solve it.

g(4) = x² + 1   Plug in 4 for x
       = 4² + 1   Square
       = 16 + 1   Add
       = 17

g(3) = x² + 1   Plug in 3 for x
       = 3² + 1   Square
       = 9 + 1   Add
       = 10

Now, put the two together.

g(4) + g(3) =    Substitute in the answers you just got.
      17 + 10 =    Add
                  = 27         

4. g(-1) = x² + 1      Substitute in -1 for x
            = (-1)² + 1   Square
            = 1 + 1        Add
            = 2

5. g(-6) = x² + 1       Plug in -6 for x
             = (-6)² + 1   Square
             = 36 + 1      Add
             = 37

For the last set, we have h(x) = x² + 7 and k(x) = 4x - 5. We'll have to pay close attention to the starting variables here.

6. h(-6) = x² + 7       Plug in -6 for x
             = (-6)² + 7   Square
             = 36 + 7      Add
             = 43

k(4) = 4x - 5     Plug in 4 for x
       = 4(4) - 5   Multiply
       = 16 - 5      Subtract
       = 11

Put the two answers into the final equation.

h(-6) + k(4) =    Substitute in the answers you got
       43 + 11 =    Add
                   = 54

7. k(10) = 4x - 5       Plug in 10 for x
            = 4(10) - 5   Multiply
            = 40 - 5      Subtract
            = 35

h(2) = x² + 7   Plug in 2 for x
       = 2² + 7   Square
       = 4 + 7     Add
       = 11

Now, put those into the equation.

k(10) - h(2) =    Plug in the answers you got
       35 - 11 =    Subtract
                  = 24

8. For this one, it wants you to add h(x) and k(x). We don't need to plug anything into the equations this time because they're both already solved for x! So, you can just set this up like a standard find-x equation.

(x² + 7) + (4x - 5) =
    x² + 7 + 4x - 5 =   Combine like terms (7 and -5)
         x² + 2 + 4x =    Reorder so the variables come first
                            = x² + 4x + 2

  
4 0
3 years ago
Read 2 more answers
Need help with my homework ​
Volgvan

Answer:

\displaystyle y=\frac{16-9x^3}{2x^3 - 3}

\displaystyle y=-\frac{56}{13}

Step-by-step explanation:

<u>Equation Solving</u>

We are given the equation:

\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}

i)

To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.

We have to make it in steps like follows.

Cube both sides:

\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3

Simplify the radical with the cube:

\displaystyle x^3=\frac{3y+16}{2y+9}

Multiply by 2y+9

\displaystyle x^3(2y+9)=\frac{3y+16}{2y+9}(2y+9)

Simplify:

\displaystyle x^3(2y+9)=3y+16

Operate the parentheses:

\displaystyle x^3(2y)+x^3(9)=3y+16

\displaystyle 2x^3y+9x^3=3y+16

Subtract 3y and 9x^3:

\displaystyle 2x^3y - 3y=16-9x^3

Factor y out of the left side:

\displaystyle y(2x^3 - 3)=16-9x^3

Divide by 2x^3 - 3:

\mathbf{\displaystyle y=\frac{16-9x^3}{2x^3 - 3}}

ii) To find y when x=2, substitute:

\displaystyle y=\frac{16-9\cdot 2^3}{2\cdot 2^3 - 3}

\displaystyle y=\frac{16-9\cdot 8}{2\cdot 8 - 3}

\displaystyle y=\frac{16-72}{16- 3}

\displaystyle y=\frac{-56}{13}

\mathbf{\displaystyle y=-\frac{56}{13}}

8 0
2 years ago
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