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2 years ago

I will like to know how to solve this

Mathematics

2 answers:

Lorico [155]2 years ago

6 0

x = 2

Collect terms in x on one side of the equation and numeric values on the other

subtract 7x from both sides

1 + 4x - 7x = - 5

1 - 3x = - 5 ( subtract 1 from both sides )

- 3x = - 5 - 1 = - 6 ( divide both sides by - 3 )

x = $\frac{- 6}{- 3}$ = 2

nikitadnepr [17]2 years ago

4 0

1 + 4x = -5 + 7x

-4x - 4x

1 = -5 + 3x

+5 +5

6 = 3x

$\frac{6}{3} = \frac{3x}{3}$

2 = x

Answer: x = 2

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$\bar{x}=\frac{\sum x}{n} = 70,000\\\\\sum x=(\bar{x})(n) = (70,000)(10)\\\\\sum x=700,000\\\\\sum x_{new} =700,000 -100,000+1,000,000\\\\\sum x_{new}=1,600,000\\\\\bar{x}_{new}=\frac{1,600,000}{10}\\\\\bar{x}_{new}=160,000$

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$\sigma=\sqrt{\frac{\sum x^{2}-n\bar{x}}{N-1}}---(1)\\\\\sigma_{new}=\sqrt{\frac{\sum x_{new}^{2}-n\bar{x}_{new}}{N-1}}---(2)\\\\From\,\, (1)\\\\\sum x^{2}=(N-1)\sigma^{2}+n\bar{x}$

$\sum x^{2}=(10-1)(60,000)^{2}+(10)(70,000)^{2}\\\\\sum x^{2}=8.14\times 10^{10}\\\\\sum x_{new}^{2}= 8.14\times 10^{10}-(10,0000)^{2}+(1,000,000)^{2}\\\\\sum x_{new}^{2}=1.0714\times 10^{12}\\\\Using\,\, (2)\\\sigma_{new}=\sqrt{\frac{1}{9}(1.0714\times 10^{12}-(10)(1.6\times 10^{5})}\\\\\sigma_{new}=\sqrt{9.06\times 10^{11}}\\\\\sigma_{new}=300998.34$

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