6x = 4y - 8
4y = 6x + 8
y = (3/2) x + 2
Answer: Slope 3/2, y intercept 2
Answer:
The answer is 65%
Step-by-step explanation: Divide 60 by 39 and multiply by 100. So it will look like 39/60=0.65*100=65%. I hope this helps. :)
Answer:
Step-by-step explanation:
For each component, there are only two possible outcomes. Either it fails, or it does not. The components are independent. We want to know how many outcomes until r failures. The expected value is given by

In which r is the number of failures we want and p is the probability of a failure.
In this problem, we have that:
r = 1 because we want the first failed unit.
![p = 0.4[\tex]So[tex]E = \frac{r}{p} = \frac{1}{0.4} = 2.5](https://tex.z-dn.net/?f=p%20%3D%200.4%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3ESo%3C%2Fp%3E%3Cp%3E%5Btex%5DE%20%3D%20%5Cfrac%7Br%7D%7Bp%7D%20%3D%20%5Cfrac%7B1%7D%7B0.4%7D%20%3D%202.5)
The expected number of systems inspected until the first failed unit is 2.5
Answer: it’s not clear I can’t see it
Step-by-step explanation:
Out of 124 students, only 31 students are taught to buy their lunches in the cafeteria.
<u>Step-by-step explanation:</u>
It is given that,
The 25% of 124 students are taught to buy their lunches in cafeteria.
Therefore, the total number of students taught to buy their lunches in cafeteria is 25% of 124.
<u>To find the number of students who are capable to buy lunches in cafeteria:</u>
- Replace the % symbol into the numeric form.
- The % is represented by 1 ÷ 100.
The 25% of 124 students is written as,
⇒ 25×(1/100)×124
⇒ (1/4)×124
⇒ 31
The number of students taught to buy lunches in the cafeteria out of 124 students is 31 students.