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ladessa [460]
3 years ago
9

Arun made a garden that was 5/6 yard long and 2/3 yard wide. Which is the area of his gardens

Mathematics
2 answers:
s2008m [1.1K]3 years ago
8 0
The area of a rectangle, which I'm assuming it is, is A= lw. Where "l" is length and "w" is width.
Gnom [1K]3 years ago
8 0
5/9
hop that this helps
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A particle moves along a line with a velocity v(t)=t2−t−6, measured in meters per second. Find the total distance the particle t
ahrayia [7]

Answer:

10.67 m

Step-by-step explanation:

Velocity is given as;

v(t) = t² − t − 6

To get the distance, we will integrate the velocity equation.

x(t) = ∫v(t) = (t³/3) - (t²/2) - 6t

Thus, from t=0 seconds to t=4 seconds., we have;

(t³/3) - (t²/2) - 6t between 0 and 4.

Thus;

Total Distance = [(4³/3) - (4²/2) - 6(4)] - [(0³/3) - (0²/2) - 6(0)]

Total distance = (64/3) - 8 - 24 = -10.67 m

Distance can't be negative and so we take the absolute value which is 10.67 m

7 0
3 years ago
Some please explain this
Dmitriy789 [7]

♡ x is 57 degress

♡ y is 44.5 degrees

♡ v is 51 degrees

♡ z is 129 degrees

5 0
3 years ago
The line AB has the midpoint of (2,5) A has coordinates (1,7) find the coordinates of B
Pavel [41]

Answer:

Point B is at (3,3)

Step-by-step explanation:

the mid point is (2,5) and A is at (1,7)

first find the slope:

y1 - y2/x1 - x2

7 - 5/1 - 2

2/-1

-2/1

then go down 2 units and right 1 unit from (2,5):

(2 + 1, 5 - 2) => (3,3)

6 0
3 years ago
Write an equation that represents degrees fahrenheit in terms of degrees celsius. let xx represent the temperature in degrees ce
IgorC [24]
As we know Conversion from fahrenheit to celsius is
F - 32 =  \frac{9C}{5}

We can write it also as

F =  \frac{9C}{5}+32

F as y and C as x then we can write it as

y =  \frac{9x}{5} + 32
7 0
3 years ago
What does an S-shaped curve for population growth suggest?
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A pattern of growth<span> in which, in a new environment, the </span>population<span> density of an organism increases slowly initially, in a positive acceleration phase; then increases rapidly, approaching an exponential </span>growth<span> rate</span>
7 0
3 years ago
Read 2 more answers
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