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ladessa [460]
3 years ago
9

Arun made a garden that was 5/6 yard long and 2/3 yard wide. Which is the area of his gardens

Mathematics
2 answers:
s2008m [1.1K]3 years ago
8 0
The area of a rectangle, which I'm assuming it is, is A= lw. Where "l" is length and "w" is width.
Gnom [1K]3 years ago
8 0
5/9
hop that this helps
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Write the equation of the line that passes through the points (2,−8) and (1,7). Put your answer in fully reduced point-slope for
ValentinkaMS [17]

Point-slope form of equation is: y - 7 = -15(x-1)

Step-by-step explanation:

Given points are:

(2,-8) and (1,7)

First of all we have to calculate the slope of the line

so,

m=\frac{y_2-y_1}{x_2-x_1}\\= \frac{7-(-8)}{1-2}\\=\frac{7+8}{-1}\\=\frac{15}{-1}\\= -15

Point-slope form is given by:

y-y_1 = m(x-x_1)

Putting the value of slope

y-y_1 = -15(x-x_1)

We can put any one of two given points in the equation to find the final form of point-slope form

So

Putting (1,7) in the equation

y - 7 = -15(x-1)

Hence, point-slope form of equation is: y - 7 = -15(x-1)

Reducing and simplifying

y - 7 = -15(x-1)\\y-7 = -15x+15\\y-7+7 =-15x+15-7\\y = -15x+8\\15x+y = 8

Keywords: Point-slope form, equation of line

Learn more about equation of line at:

  • brainly.com/question/6200750
  • brainly.com/question/568302

#LearnwithBrainly

8 0
3 years ago
I got this problem wrong and I have no idea how to solve it.<br>Help please ☕​
astra-53 [7]

Answer:

Step-by-step explanation:

8 0
2 years ago
What is y&lt;-x+5 and y≤ 2x-1??
olga nikolaevna [1]

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

The pair of inequalities is graphed in the attachment.

The first inequality graphs as a shaded area below the dashed line y=-x+5.

The second inequality graphs as a shaded area below the solid line y=2x-1.

The solution set is the doubly-shaded area below the point where the lines intersect.

3 0
3 years ago
Please help I know how to do this but there’s too much
Lady_Fox [76]

Answer: See attached images

Step-by-step explanation:

For third period:

Minimum = 67

1st Quartile: 79.5

Median/2nd Quartile: 85

3rd Quartile: 90.5

Maximum = 99

I've attached the image for this class's box plot.

For Sixth Period:

Minimum = 70

1st Quartile: 79.5

Median/2nd Quartile: 88

3rd Quartile: 90.5

Maximum = 95

I've also attached the image for this class's box plot

6 0
2 years ago
10 points help please help me no understand math
guajiro [1.7K]

Answer:

TX

Step-by-step explanation:

7 0
2 years ago
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