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ad-work [718]
3 years ago
9

A store sells 6 T-shirts for $59.34. What is the unit cost per T-shirt?

Mathematics
2 answers:
KonstantinChe [14]3 years ago
8 0
The answer is A. Multiply 6 times 59.34
Zinaida [17]3 years ago
5 0

Answer:

$9.89

Step-by-step explanation:

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Sarah has a collection of nickels, dimes, and quarters worth $13.80. she has 10 more dimes than nickels and twice as many quarte
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The whole cake is 9 cm high and 20 cm across. Each layer of cake is 2cm thick, and each layer is separated by 1 cm of frosting.
Digiron [165]

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PO

Step-by-step explanation:

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3 years ago
A recursive rule for an arithmetic sequence is a1=−3;an=an-1+7
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C is the answer. Hope you get a good grade
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Read 2 more answers
According to an​ airline, flights on a certain route are on time 8080​% of the time. Suppose 1111 flights are randomly selected
Sergio [31]

Answer:

a. This experiment satisfy the conditions below.

b. 0

c. 0

d. 1

e. 0

Step-by-step explanation:

a. This experiment satisfy the following conditions:

1. The experiment consists of n = 1111 identical trials, i.e., to determine if each flight is on-time or not.

2. Each trial results in success or failure, i.e., the flight is on-time or not.

3. The probability of success in each trial is the same, p = 0.8, because a flight is on-time 80% of the time.

4. The trials are independent because the 1111 flights were selected randomly.

5. Te random variable of interest is Y, the number of on-time flights observed in the n = 1111 flights.

b. P(Y = 99) = \frac{1111!}{99!(1111-99)!}(0.8)^99(0.2)^{1111-99} = 0. This is the probability that 99 flights are on time and 1012 are not.

c. P(Y < 99) = \sum_{i=1}^{98}\frac{1111!}{y!(1111-y)!}(0.8)^y(0.2)^{1111-y} = 0. This is the probability that 0 flights are on-time or 1 flight is on-time or ... or 98 flights are on-time.

d. 1 - P(Y < 99) = 1 - 0 = 1. This is the probability that 99 flights are on-time or 100 flights are on-time or ... or all 1111 flights are on-time.

e. P(77\leq Y \leq 99) = \sum_{i=77}^{99}\frac{1111!}{y!(1111-y)!}(0.8)^y(0.2)^{1111-y} = 0 This is the probability that 77  flights are on-time or 78 flights are on-time or ... or 99 flights are on-time.

8 0
3 years ago
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