Answer:
We conclude that the equation in slope-intercept form of the line that passes through (12,9) and is perpendicular to the graph of y = -3/4x + 1 will be:
Step-by-step explanation:
We know the slope-intercept form of the line equation
y = mx+b
where
Given the line
y = -3/4x + 1
comparing with the slope-intercept form of the line equation
The slope = m = -3/4
We know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line, such as:
slope = m = -3/4
Thus, the slope of the new perpendicular line = – 1/(-3/4) = 4/3
Using the point-slope form
where m is the slope of the line and (x₁, y₁) is the point
substituting the values of the slope = 4/3 and the point (12, 9)
Add 9 to both sides
Therefore, we conclude that the equation in slope-intercept form of the line that passes through (12,9) and is perpendicular to the graph of y = -3/4x + 1 will be:
I’m pretty sure answer is A and i’m
In a hand of 5 cards, you want 4 of them to be of the same rank, and the fifth can be any of the remaining 48 cards. So if the rank of the 4-of-a-kind is fixed, there are 
possible hands. To account for any choice of rank, we choose 1 of the 13 possible ranks and multiply this count by 
. So there are 624 possible hands containing a 4-of-a-kind. Hence A occurs with probability
There are 4 aces in the deck. If exactly 1 occurs in the hand, the remaining 4 cards can be any of the remaining 48 non-ace cards, contributing 
possible hands. Exactly 2 aces are drawn in 
hands. And so on. This gives a total of
possible hands containing at least 1 ace, and hence B occurs with probability
The product of these probability is approximately 0.000082.
A and B are independent if the probability of both events occurring simultaneously is the same as the above probability, i.e. 
. This happens if
- the hand has 4 aces and 1 non-ace, or
- the hand has a non-ace 4-of-a-kind and 1 ace
The above "sub-events" are mutually exclusive and share no overlap. There are 48 possible non-aces to choose from, so the first sub-event consists of 48 possible hands. There are 12 non-ace 4-of-a-kinds and 4 choices of ace for the fifth card, so the second sub-event has a total of 12*4 = 48 possible hands. So 
consists of 96 possible hands, which occurs with probability
and so the events A and B are NOT independent.
You just have to answer to all of the questions and bullet points. Think about them, and do some sketches. In the end that will help you to end the assignment.
Hope it helped.
