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Anna [14]
2 years ago
6

How many cubes with side lengths of 1/3 cm does it take to fill the prism?

Mathematics
1 answer:
user100 [1]2 years ago
8 0

Answer:

The number of cubes that fill the prism is 24

Step-by-step explanation:

Given as :

The length of cube (l) = \frac{1}{3} cm

The length of prism (L) = 1 cm

The width of prism (w) = 2 \frac{2}{3} = \frac{8}{3} cm

The height of prism (h) = \frac{2}{3} cm

Let the number of cubes that fill the prism = x

Now, Volume of cube with length (l) = l³   cm³

Or,  Volume of cube with length (l) = (\frac{1}{3})^{3}  cm³

Or,  Volume of cube with length (l) = (\frac{1}{27})  cm³

Again , Volume of prism  = \frac{1}{2}\times Length \times width \times height

Or, Volume of prism = \frac{1}{2}\times 1 \times \frac{8}{3} \times \frac{2}{3}

Or, Volume of prism = (\frac{8}{9})  cm³

<u>So , The number of cubes to fill prism  </u>

 The number of cubes × Volume of cube = Volume of prism

Or, x × (\frac{1}{27})  cm³ = (\frac{8}{9})  cm³

or   x = \frac{8\times 27}{9} = 24

Hence The number of cubes which fill the prism is 24  Answer

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Hope this helps!

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2 years ago
Given A = {(1, 3)(-1, 5)(6, 4)}, B = {(2, 0)(4, 6)(-4, 5)(0, 0)} and C = {(1, 1)(0, 2)(0, 3)(0, 4)(-3, 5)}, answer the following
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  Domain of set B: {2, 4, -4, 0}

Step-by-step explanation:

The domain of the function whose ordered pairs are listed in set B is the set of first numbers of those pairs: {2, 4, -4, 0}.

_____

<em>Comment on the question</em>

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Step-by-step explanation:

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Put the differential equation 9ty+ety′=yt2+81 into the form y′+p(t)y=g(t) and find p(t) and g(t). p(t)= help (formulas) g(t)= he
alexgriva [62]

Answer:

p(t) = \frac{9t^{3} + 729t  - 1}{e^{t}(t^{2} + 81) }

g(t) = 0

And

The differential equation 9ty + e^{t}y' = \frac{y}{t^{2} + 81 } is  linear and homogeneous

Step-by-step explanation:

Given that,

The differential equation is -

9ty + e^{t}y' = \frac{y}{t^{2} + 81 }

e^{t}y' + (9t - \frac{1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t(t^{2} + 81 ) - 1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t^{3} + 729t  - 1}{t^{2} + 81 } )y = 0\\y' + [\frac{9t^{3} + 729t  - 1}{e^{t}(t^{2} + 81) } ]y = 0

By comparing with y′+p(t)y=g(t), we get

p(t) = \frac{9t^{3} + 729t  - 1}{e^{t}(t^{2} + 81) }

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And

The differential equation 9ty + e^{t}y' = \frac{y}{t^{2} + 81 } is  linear and homogeneous.

6 0
2 years ago
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