System A has ONE real solution
System B has NO real solutions
System C has ONE real solution
and 
use the second expression to calculate the left-hand side of the first equation:
Add 10 to both sides if this equation to get
and divide both sides by 2
this proves that x = 17, give the two initial equations
I believe x is 0 because if we assume y and x are 0 then 0=0 and 0= 5 x 0
Answer:
−6x^2+7x+1
Step-by-step explanation:
1)(7x+8x-4)=15x−4
2)15x-4-(6x^2+8x-5)=−6x2+7x+1
Answer: The answer is not -7 it is in fact -31.
Step-by-step explanation:
5 - ( 6^2 ) / 4 - 3
6^2 = 36
5 - ( 6^2 ) = -31
4 - 3 = 1
5 - 36 / 1 = -31 / 1 = -31
So anything divided by 1 is = to itself.
