Answer:
The two products that will be formed are:
Ca(NO3)2
NaI
Explanation:
When NaNO3 reacts with CaI2, double substitution reaction takes place.
This means that I2 and NO3 will each substitute the other.
The chemical reaction used to explain this is as follows:
2NaNO3 + CaI2 .........> 2NaI + Ca(NO3)2
Hope this helps :)
Part A answer is C. - central idea
Part B answer is C. - supports central idea
Part A answer is D. - what the author thinks
Part B answer is A. - supports what the author thinks
Answer : The measurement units were biased.
Explanation : While the wildlife researcher weighed all the raccoons that were trapped only in the suburban neighborhood neglected the count of the raccoons in whole state. As per the statement stated in the problem "weighed all the raccoons that were trapped in suburban neighborhoods" clearly shows the confirmation of the same.
Answer:
.0027 M
Explanation:
We must calculate the threshold concentration of PO3−4 using Ksp and the given concentration of Ca2+:
Ca3(PO4)2(s)⇌3Ca2+(aq)+2PO3−4(aq)
Ksp=8.6×10−19=[Ca2+]3[PO3−4]2=(4.9×10−5M)3[PO3−4]2
[PO3−4]=0.0027 M
Answer:
506.912 L
Explanation:
From the question given above, the following data were obtained:
Number of mole of O₂ = 22.63 moles
Volume of O₂ =?
Recall:
1 mole of a gas occupy 22.4 L at STP.
With the above information, we obtained the volume occupied by 22.63 moles of O₂ as follow:
1 mole of O₂ occupied 22.4 L at STP.
Therefore, 22.63 moles of O₂ will occupy = 22.63 × 22.4 = 506.912 L at STP.
Thus, 22.63 moles of O₂ is equivalent to 506.912 L.