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balu736 [363]
3 years ago
13

Question: convert 22.63 miles of oxygen to volume very urgent

Chemistry
1 answer:
Stels [109]3 years ago
3 0

Answer:

506.912 L

Explanation:

From the question given above, the following data were obtained:

Number of mole of O₂ = 22.63 moles

Volume of O₂ =?

Recall:

1 mole of a gas occupy 22.4 L at STP.

With the above information, we obtained the volume occupied by 22.63 moles of O₂ as follow:

1 mole of O₂ occupied 22.4 L at STP.

Therefore, 22.63 moles of O₂ will occupy = 22.63 × 22.4 = 506.912 L at STP.

Thus, 22.63 moles of O₂ is equivalent to 506.912 L.

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A 32.2 g iron rod, initially at 21.9 C, is submerged into an unknown mass of water at 63.5 C. in an insulated container. The fin
lorasvet [3.4K]

Answer : The mass of the water in two significant figures is, 3.0\times 10^1g

Explanation :

In this case the heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of iron metal = 0.45J/g^oC

c_2 = specific heat of water = 4.18J/g^oC

m_1 = mass of iron metal = 32.3 g

m_2 = mass of water = ?

T_f = final temperature of mixture = 59.2^oC

T_1 = initial temperature of iron metal = 21.9^oC

T_2 = initial temperature of water = 63.5^oC

Now put all the given values in the above formula, we get

32.3g\times 0.45J/g^oC\times (59.2-21.9)^oC=-m_2\times 4.18J/g^oC\times (59.2-63.5)^oC

m_2=30.16g\approx 3.0\times 10^1g

Therefore, the mass of the water in two significant figures is, 3.0\times 10^1g

3 0
3 years ago
What product(s) would be formed when these are the reactants? C5H12 + O2 (limited)
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