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podryga [215]
3 years ago
13

A NaOH(aq) solution with a pH value of 13 is used to determine the molarity of a HCl(aq) solution. A 10.0-mL sample of the HCl(a

q) is exactly neutralized by 16.0 mL of 0.100 M NaOH(aq). During this laboratory activity, appropriate safety equipment was used and safety procedures were followed. Determine the pH value of a solution that has a H+(aq) ion concentration 10 times greater than the original NaOH(aq) solution.
Chemistry
1 answer:
erica [24]3 years ago
5 0

Answer:

pH of the H⁺(aq) is 0

Explanation:

It is possible to know the  concentration of a HCl(aq) solution by titration with a solution of NaOH(aq) with known concentration. The reaction is:

HCl(aq) +  NaOH(aq) → H₂O(l) + NaCl(aq)

The added moles of NaOH are equal to moles of HCl and as you know volume of HCl added you will obtain concentration of HCl.

Now, a solution of H⁺(aq) with a concentration 10 times greater than original NaOH(aq) solution -0.100M-, has a concentration of 1.00M H⁺(aq), the pH of this solution is:

pH = -log (1.00M H⁺(aq) = 0

That means <em>pH of the H⁺(aq) is 0</em>

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Write a balanced net ionic equation for the reaction of aqueous solutions of baking soda (NaHCO3) and acetic acid.(A) HCO3–(aq)
IgorC [24]

<u>Answer:</u> The correct answer is Option C.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of sodium bicarbonate and acetic acid is given as:

NaHCO_3(aq.)+CH_3COOH(aq.)\rightarrow CH_3COONa(aq.)+H_2O(l)+CO_2(g)

Ionic form of the above equation follows:

Na^+(aq.)+HCO_3^-(aq.)+CH_3COO^-(aq.)+H^+(aq.)\rightarrow CH_3COO^-(aq.)+Na^+(aq.)+H_2O(l)+CO_2(g)

As, sodium and acetate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

HCO_3^-(aq.)+H^+(aq.)\rightarrow CO_2(g)+H_2O(l)

Hence, the correct answer is Option C.

8 0
2 years ago
Rank the members of each set of compounds in order of decreasing ionic character of their bonds. Use partial charges to indicate
Firdavs [7]

Answer:

Ionic character

A.  PF₃ > PBr₃ > PCl₃

B. BF₃ > CF₄ > NF₃

C. TeF₄ > BrF₃ > SeF₄

Explanation:

The most electronegative element is fluorine, followed chlorine, phosphorous nitrogen etc.

  • Atoms with high electronegativity tend to form negative ions.
  • Ionic compounds formed between elements with high electronegativity difference.
  • % ionic character is directly proportional to electronegativity difference.
  • According to Pauling Scale E.n for F(4.0), O(3.5), N(3.0), C(2.5), B(2.0), P(2.19), Se(2.55) , Te (2.1), Cl(3.16) and Br(2.96)
  • ΔE.N (Electronegativity difference) between( P and F = 4 - 2.19 = 1.81), (P and Br = 2.96 - 2.19 = 0.77) , (P and Cl = 3.16 - 2.96 = 0.2 )
  • ΔE.N (Electronegativity difference) between( N and F = 4 - 3 = 1), (B and F = 4 - 2 = 2) , (C and F = 4 - 2.5 = 1.5 )
  • ΔE.N (Electronegativity difference) between( Se and F = 4 - 2.55 = 1.45), (F and Te = 4 - 2.1 = 1.9) , (F and Br = 4 - 2.19 = 1.81 )

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3 years ago
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29.3g CO2 and 20.8g H2O
docker41 [41]

Answer:

the most best answer is 50.1 you never find such type of answer

6 0
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Mrrafil [7]

Answer:

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