a quarter horse can run 53.16 mile per hour. a garden snail moves at 0.02 miles per hour. how much faster is the quarter horse t
2 answers:
Answer:
<h2>The horse is 2658 times faster than the snail.</h2>Step-by-step explanation:
Givens
- The quarter horse can run 53.16 miles per hour.
- The garden snail moves at 0.02 miles per hour.
To know how much faster is the quarter horse than the snail, we just need to express as the following equation
Where is the horse and
is the snail, replacing each value we have
Where represents the factor that makes the horse faster. Now we solve
Therefore, the horse is 2658 times faster than the snail.
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Answer:
Step-by-step explanation:
From the picture attached,
9). When pre-image KLMN is a reflected across x = -2, we get image K'L'M'N'.
Therefore, line of reflection will be x = -2
10). In this picture line of reflection which passes through origin (0, 0) and slope = 1 will be,
y = x.
11). Since, all the points of image and preimage points are equidistant from x-axis, line of reflection will be x-axis or y = 0.
12). Line passing through midpoint of the line joining BB' will be the line of reflection.
Coordinates of B → (5, 3)
Coordinates of B' → (5, 7)
Coordinates of BB' → → (5, 5)
Therefore, line of reflection will be y = 5.
13). Coordinates of G → (2, 5)
Coordinates of G' → (-2, 5)
Midpoint joining the segment GG' → → (0, 5)
Therefore, line of reflection → x = 0
14). Line of reflection passing through (0, 0) and slope = -1
y = -x