Answer:
20.996 m
Explanation:
Given:
Initial velocity, 
Final velocity, 
Total time taken, 
s.
∴ Acceleration is given as,
m/s²
Now, using Newton's equation of motion, we find the displacement.
Displacement is given as:
Plug in 0 for 
, 4.91257 for 
and 1.74 for 
. Solve for 
.
This gives,
Therefore, the train's displacement in the first 4.91257 s of motion is 20.996 m.
Answer:
See solution below
Explanation:
The standard equation of a wave is represented by: Y = Asin 2π(x/λ – ft)
A is the amplitude
λ is the wavelength
f is the frequency
t is the time
Comparing the standard with the given equation Y = 0.005sin 2π(0.5x – 200t)
i) A = 0.005m
Amplitude is 0.005m
ii) ω = 2πf
ω = 2π(200)
ω = 400π rad/s
iii) ω = 2πf
400π = 2πf
200 = f
Swap
f = 200Hertz
iv) Period = 1/f
Period = 1/200
Period = 0.005secs
v) wave number =
vi) Wavelength λ
0.5x = x/λ
0.5 = 1/λ
λ = 1/0.5
λ = 2m
vii) velocity - fλ
velocity = 200 * 2
velocity = 400m/s
Answer: the answer is A
Explanation: im pretty sure this is right, its been a little bit since i had to study this
