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spin [16.1K]
3 years ago
9

A cruise ship makes its way from one island to another. The ship is in motion compared with which reference point?

Physics
2 answers:
diamong [38]3 years ago
8 0
C theres a light house near by

Crank3 years ago
5 0

Answer:

C) a lighthouse on a nearby island

Explanation:

Rate of change in position of an object with time is known as motion

So here ship will be in motion with respect of all that objects which will see the change in position of ship with time.

So here we can say all those objects which are lying on the ship itself will move along with the ship so these objects will not observe the change in the position of the ship.

While all object which are lying outside the ship can observe the change in the position of the ship

So correct answer will be

C) a lighthouse on a nearby island

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The pilot of an airplane notes that the compass indicates heading west. The airplane's speed relative to the air is 100 km/h. Th
irinina [24]
The airplane's speed relative to the ground is

                                     √ (100² + 25²)

                                 =  √ (10,000 + 625)

                                 =  √ 10,625

                                 =      103.08  km/hr .

The angle of its velocity north of west is
the angle whose tangent is  (25/100)

                         arctan(25/100) = 14° north of west .

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6 0
3 years ago
What can we say about the rock as it falls to Earth?
igor_vitrenko [27]

B) It falls at a constant rate of speed.


8 0
4 years ago
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Like the alto in a choir the octavina plays the lower melody . what musical element does this tell?
Katena32 [7]

<em>L</em><em>ike the alto in a choir the octavina plays the lower melody . what musical element does this tell?</em>

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7 0
3 years ago
Please help Need good grade
ivann1987 [24]

Answer:

The other angle is 120°.

Explanation:

Given that,

Angle = 60

Speed = 5.0

We need to calculate the  range

Using formula of range

R=\dfrac{v^2\sin(2\theta)}{g}...(I)

The range for the other angle is

R=\dfrac{v^2\sin(2(\alpha-\theta))}{g}....(II)

Here, distance and speed are same

On comparing both range

\dfrac{v^2\sin(2\theta)}{g}=\dfrac{v^2\sin(2(\alpha-\theta))}{g}

\sin(2\theta)=\sin(2\times(\alpha-\theta))

\sin120=\sin2(\alpha-60)

120=2\alpha-120

\alpha=\dfrac{120+120}{2}

\alpha=120^{\circ}

Hence, The other angle is 120°

6 0
4 years ago
Water flows at 0.65 m/s through a 3.0 cm diameter hose that terminates in a 0.3 cm diameter nozzle. (Recall, the density of wate
xeze [42]

Answer:

v2 = 65 m/s

the speed of the water leaving the nozzle is 65 m/s

Explanation:

Given;

Water flows at 0.65 m/s through a 3.0 cm diameter hose that terminates in a 0.3 cm diameter nozzle

Initial speed v1 = 0.65 m/s

diameter d1 = 3.0 cm

diameter (nozzle) d2 = 0.3 cm

The volumetric flow rates in both the hose and the nozzle are the same.

V1 = V2 ........1

Volumetric flow rate V = cross sectional area × speed of flow

V = Av

Area = (πd^2)/4

V = v(πd^2)/4 ....2

Substituting equation 2 to 1;

v1(πd1^2)/4 = v2(πd2^2)/4

v1d1^2 = v2d2^2

v2 = (v1d1^2)/d2^2

Substituting the given values;

v2 = (0.65 × 3^2)/0.3^2

v2 = 65 m/s

the speed of the water leaving the nozzle is 65 m/s

6 0
4 years ago
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