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sergiy2304 [10]
3 years ago
7

Plz help asap!!! I will mark brainliest for right answer....

Physics
2 answers:
RoseWind [281]3 years ago
6 0
Yes some mixtures can be separated lets say sand and water the sand is insoluble therefore you can separate it using filtration  so it really depends on the mixture but yes they can be
matrenka [14]3 years ago
3 0
Yes mixtures can be separated....by using some methods like fractional distillation,sublimation,filteration etc
As mixtures are of two types homogeneous and heterogeneous it depends upon the mixtures that how they'll be separated like if u take a mixture of iron granules and sugar then u will use magnet for mixture of water and sugar u will use evaporation method if sugar and salt is mixed then put the solution in alcohol then one of them either sugar or salt will be eliminated
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When low on gasoline, is it better to increase or decrease the speed of the vehicle? Explain.
sergiy2304 [10]
Yeah!! It is better to decrease the speed of the vehicle so the ejection of gases would happen in slow manner.... then you can save your gasoline
5 0
3 years ago
I need help please...
Natalka [10]
No cluuuueee :/ sowwwwyyy but good luck
6 0
3 years ago
Read 2 more answers
What is temperature?
FromTheMoon [43]

Answer:

B a measure of the amount of matter in an object

8 0
3 years ago
A potential difference of 24 V is applied to a 150-ohm resistor. How much current flows through the resistor?​
Lady_Fox [76]

Given :- A resistor of 150 ohm, hence Resistance (R) = 150 ohm

Potential Difference (v) = 24 V

Current (I) = ?

V = IR

24 = I × 150

I = 24/150

I = 0.16 ampere

hope it helps!

3 0
3 years ago
Suppose that an asteroid traveling straight toward the center of the earth were to collide with our planet at the equator and bu
vlada-n [284]

Answer:

\frac{1}{10}M

Explanation:

To apply the concept of <u>angular momentum conservation</u>, there should be no external torque before and after

As the <u>asteroid is travelling directly towards the center of the Earth</u>, after impact ,it <u>does not impose any torque on earth's rotation,</u> So angular momentum of earth is conserved

⇒I_{1} \times W_{1} =I_{2} \times W_{2}

  • I_{1} is the moment of interia of earth before impact
  • W_{1} is the angular velocity of earth about an axis passing through the center of earth before impact
  • I_{2} is moment of interia of earth and asteroid system
  • W_{2} is the angular velocity of earth and asteroid system about the same axis

let  W_{1}=W

since \text{Time period of rotation}∝\frac{1}{\text{Angular velocity}}

⇒ if time period is to increase by 25%, which is \frac{5}{4} times, the angular velocity decreases 25% which is \frac{4}{5}  times

therefore W_{1} = \frac{4}{5} \times W_{1}

I_{1}=\frac{2}{5} \times M\times R^{2}(moment of inertia of solid sphere)

where M is mass of earth

           R is radius of earth

I_{2}=\frac{2}{5} \times M\times R^{2}+M_{1}\times R^{2}

(As given asteroid is very small compared to earth, we assume it be a particle compared to earth, therefore by parallel axis theorem we find its moment of inertia with respect to axis)

where M_{1} is mass of asteroid

⇒ \frac{2}{5} \times M\times R^{2} \times W_{1}=}(\frac{2}{5} \times M\times R^{2}+ M_{1}\times R^{2})\times(\frac{4}{5} \times W_{1})

\frac{1}{2} \times M\times R^{2}= (\frac{2}{5} \times M\times R^{2}+ M_{1}\times R^{2})

M_{1}\times R^{2}= \frac{1}{10} \times M\times R^{2}

⇒M_{1}=}\frac{1}{10} \times M

3 0
3 years ago
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