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2 years ago

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A firecracker breaks up into three pieces, one of which has a mass of 200 g and flies off along the x-axis with a speed of 82.0

m/s. A second piece has a mass of 300 g and flies off along the y-axis with a speed of 45.0 m/s. (a) What is the magnitude of the momentum for the third piece

1 answer:

Mamont248 [21]2 years ago

8 0

Answer:

$|P_3|=21.242m/s$

Explanation:

From the question we are told that:

Mass $m=200g=0.2$

Speed $v=82.0m/s$

Mass $M_2=300g=0.3kg$

Speed $V_2=45.0m/s$

Generally the equation for Magnitude of the Third piece is mathematically given by

$P_1+P_2+P_3=0$

$|P_3|=|P_1+P_2|$

Where

$P_1=m_1v_1$

$P_1=0.2*82$

$P_1=16.4kgm/s$

And

$P_2=0.3*45$

$P_2=13.5kgm/s$

Therefore

$|P_3|=\sqrt{16.4^2+13.5^2}$

$|P_3|=21.242m/s$

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