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BartSMP [9]
3 years ago
8

A firecracker breaks up into three pieces, one of which has a mass of 200 g and flies off along the x-axis with a speed of 82.0

m/s. A second piece has a mass of 300 g and flies off along the y-axis with a speed of 45.0 m/s. (a) What is the magnitude of the momentum for the third piece
Physics
1 answer:
Mamont248 [21]3 years ago
8 0

Answer:

|P_3|=21.242m/s

Explanation:

From the question we are told that:

Mass m=200g=0.2

Speed v=82.0m/s

Mass M_2=300g=0.3kg

Speed V_2=45.0m/s

Generally the equation for Magnitude of the Third piece is mathematically given by

P_1+P_2+P_3=0

|P_3|=|P_1+P_2|

Where

P_1=m_1v_1

P_1=0.2*82

P_1=16.4kgm/s

And

P_2=0.3*45

P_2=13.5kgm/s

Therefore

|P_3|=\sqrt{16.4^2+13.5^2}

|P_3|=21.242m/s

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