Answer:
A measured force of (46.5 0.8 N ) would not be in agreement with a theoretically calculated force of (48.4 0.6 N )
Explanation:
From the question we are told that
Measured force is ![F_M = [46.5 \pm 0.8 \ N ]](https://tex.z-dn.net/?f=F_M%20%20%3D%20%20%5B46.5%20%5Cpm%200.8%20%5C%20%20N%20%5D)
Calculated force is ![F_c = [48.4 \pm 0.6 \ N ]](https://tex.z-dn.net/?f=F_c%20%3D%20%20%5B48.4%20%5Cpm%200.6%20%5C%20%20N%20%5D)
Generally the measured force in interval form is
=> 
Generally the calculated force in interval form is
=> 
Generally looking both interval we see that they do not intersect at any point Hence
A measured force of (46.5 0.8 N ) would not be in agreement with a theoretically calculated force of (48.4 0.6 N )
Answer:
The breast bone is anterior to the spine. The collarbone is superior to the shoulder blade. The elbow is proximal to the wrist. The navel is distal to the chin.
Explanation:
The spine, also known as the backbone, is posterior to the breast bone.
The collarbone (also known as the clavicle), which is part of the shoulder girdle, lies superior in position to the shoulder blade (also known as the scapula).
The elbow is the joint between the arm and the wrist. it is proximal to the wrist.
The navel, located on the anterior abdominal wall, is distal to the chin that is part of the face.
Let <em>F</em> be the magnitude of the force needed to keep the box sliding at constant speed, and <em>f</em> the magnitude of kinetic friction. Then by Newton's second law, the net horizontal force on the crate is
<em>F</em> - <em>f</em> = 0
so that
<em>F</em> = <em>f</em>
<em />
<em>f</em> is proportional to the magnitude of the normal force <em>n</em>,
<em>f</em> = 0.38<em>n</em>
The net vertical force is
<em>n</em> - <em>mg</em> = 0
which tells us that
<em>n</em> = <em>mg</em> = (29 kg) (9.8 m/s²) ≈ 284 N
Then the required force must have magnitude
<em>F</em> = <em>f</em> = 0.38 (284 N) ≈ 110 N
