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Serggg [28]
3 years ago
5

Evaluate

Mathematics
1 answer:
VMariaS [17]3 years ago
3 0

Answer:

  -3/4

Step-by-step explanation:

A calculator can work this for you. All you need to do is substitute the numbers for the variables.

  yx^y -xy^x

  = 4(1/2)^4 -(1/2)(4^(1/2))

  = 4/16 - 1/2√4 = 1/4 - 1

  = -3/4

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An unprepared student makes random guesses for the ten​ true-false questions on a quiz. Find the probability that there is at le
hoa [83]

Answer:

0.999

Step-by-step explanation:

At least 1 correct means, 1 correct, 2 correct, 3 correct ... until 10 correct. That would be a long process to calculate.

<em>Instead we use the complement rule to calculate.</em>

<em>P(x\geq1)=1-P(x</em>

<em />

<em>So we need to find P(x<1). So this is getting 0 answers correct, or 10 incorrect.</em>

<em />

In true false question, probablity of correct is 1/2 and incorrect is 1/2, hence,

Probability of 10 incorrect is (1/2)^10

Thus,

P(x\geq1)=1-(\frac{1}{2})^{10}=0.999

So the answer is 0.999 (rounded to nearest thousandth)

3 0
3 years ago
There are two spinners. The first spinner has three equal sectors labeled 1, 2, and 3. The second spinner has four equal sectors
zhuklara [117]
<h3>Answer: A) 1</h3>

=========================

Explanation:

Let's label each pair of outcomes as an ordered pair (x,y)

x = first spinner outcome

y = second spinner outcome

We have these 12 different possible combos

(1,3),   (1,4),   (1,5),   (1,6)

(2,3),  (2,4),  (2,5),  (2,6)

(3,3),  (3,4),   (3,5),  (3,6)

Focus on the third column where y = 5 for each (x,y) pair. Of this column only (2,5) has x be an even number. The other results in that column have x be odd.

Basically (1,5) is the only possible outcome if we want the first spinner to lan on an even number, and the second spinner to land on 5.

7 0
4 years ago
Question 1
Cerrena [4.2K]
#1) 4 weeks, $280
#2) (5, 38)
#3) (1, 3)
#4) Step 3
#5) (y+z=6)*-8
#6) 2x+2y=8

Explanation
#1) Setting them equal,
60x+40=50x+80

Subtract 50x from both sides:
60x+40-50x=50x+80-50x
10x+40=80

Subtract 40 from both sides:
10x+40-40=80-40
10x=40

Divide both sides by 10:
10x/10 = 40/10
x=4

Plugging this in to one of our equations,
60(4)+40=240+40=280

#2) Setting the equations equal to one another, 
8x-2=9x-7

Subtract 8x from both sides:
8x-2-8x=9x-7-8x
-2=x-7

Add 7 to both sides:
-2+7=x-7+7
5=x

Plugging this in to the first equation,
8(5)-2=y
40-2=y
38=y

#3) Substituting our value from the second equation into the first one,
n-2+3n=10

Combining like terms,
4n-2=10

Add 2 to both sides:
4n-2+2=10+2
4n=12

Divide both sides by 4:
4n/4 = 12/4
n=3

Substitute this into the second equation:
m=3-2=1

#4) The mistake was made on Step 3; the 4 was left off when the equations were added.

#5) To eliminate y, we want the coefficients to be the same.  To accomplish this, we will multiply the first equation by -8.

#6) In order to have infinitely many solutions, we want each coefficient as well as the constant to be a multiple of our equation.  Multiplying the equation by 2, we get 2x+2y=8.
8 0
3 years ago
Read 2 more answers
If x^2 = 7, what is the value of x?
SpyIntel [72]

Step-by-step explanation:

{x}^{2}  = 7 \\  \\  \implies \: x =  \sqrt{7}  \\  \\  \implies \: x = 2.65

5 0
3 years ago
One approximate solution to the equation cos x = -0.60 for the domain 0° ≤ x ≤ 360° is
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5 0
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