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3 years ago

3/8(n+10)=6 what does n=

Mathematics

1 answer:

katrin2010 [14]3 years ago

3 0

$\dfrac{3}{8}(n+10)=6|\cdot8\\
3(n+10)=48\\
3n+30=48\\
3n=18\\
n=6
$

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Increase a length of 24m so that the ratio of the new length to the old length is 11:8.

murzikaleks [220]

Answer:

33m

Step-by-step explanation:

If the ratio of the new length to the old length is 11:8 (simplified ratio)

I like to set up a proportion, like this,

x/24 = 11/8, where x is the undefined new length

x*8 = 24*11 (cross multiply)

8x = 264 (multiply)

x = 33 (divide 8 by both sides)

The new length is 33m.

<em>Hope I helped! Good Luck!</em>

6 0

3 years ago

Read 2 more answers

HELP PLEASE!

Nataliya [291]

The answer is C.

The probability of a hit is 127/369 This includes home runs.The probability of a home run is 21/369 = 7/123The probability of a hit that is not a home run is (127-21)/369 = 106/369The probability of no hit is (369-127)/369 = 242/369 Now,If Miguel hits a home run, he'll score 5 pointsIf Miguel has a hit that is not a home run, he'll score 1 pointIf Miguel does not get a hit, he'll score 0 points. Expected value of his score at each at bat is(0) 242/369 + (1) 106/369 + (5) 21/369106/369 + 105/369 = 211/369 = .57

7 0

4 years ago

On a citrus farm, the average annual yield of oranges is 124 pounds per tree when the number of trees is 22 per acre. For each a

ELEN [110]

Answer:

Number of orange trees = 3528

Step-by-step explanation:

Given: Average annual orange yield = 124 pounds (lbs) per tree

Number of trees = 22 per acre

Each tree produces 124 pounds, so 22 trees will produce

124*22 = 2728 lbs per acre

For every additional tree over 22, 2 pounds per tree is lost.

So, if you add x trees, you lose 2x pounds.

Thus, we have the function:

f(x) = (124 - 2x)*(22 + x) for the added tree(s)

$f(x) = 2728 + 80x - 2x^{2}$

For quadratic equations like this, the maximum(or minimum) is obtained by substituting x= -b/2a into the given equation. a and b are obtained from the general form of a quadratic equation:

$y =ax^{2} + bx + c$

Comparing this with f(x), we have that

a = -2 (coefficient of x2)

b = 80 (coefficient of x)

Using these values in x = -b/2a, we get

$x = -\frac{80}{2*(-2)} = 20$

So, use x = 20 in the maximum function we got earlier

$f(x) = 2728 + 80(20) -2(20^{2}) = 2728 + 1600 - 800\\ \\f(x) = 3528$

Therefore, the number of oranges that should be planted in order to maximize the number of pounds of oranges per acre = 3528

3 0

3 years ago

Help it due ASAP....

VikaD [51]

The answer is b because those are angles on the opposite side of the transversal

7 0

3 years ago

Del dinero que tenía gasté 1/3 en comida y 1/8 en pasaje, quedándome aún 39 pesos. ¿Cuánto tenía al principio?

ruslelena [56]

Answer: 72 pesos.

Step-by-step explanation:

Supongamos que al principio tenias X, donde X representa la cantidad de dinero que tenias en un principio.

Gastaste:

X/3 en comida

X/8 en pasaje.

Entonces el gasto total es:

X/3 + X/8 = X*(1/3 + 1/8) = X*(11/24)

Entonces el dinero que te queda es:

X - X*(11/24) = X*(13/24) = 39 pesos.

X = (24/13)*39 pesos = 72 pesos

Al principio tenias 72 pesos.

6 0

3 years ago