Multiply everything in the parenthesis by 3.
9x - 24 = 4x + 6
Add 24 to both sides.
9x = 4x + 30
Subtract 4x from both sides.
5x = 30
Divide both sides by 5.
x = 6
Hope this helps!
Note that the formula for the circumference of a circle is πd, while the formula for the area of a circle is πr².
π≈3.14
A. C=πd
Simply plug in the numbers into the formula.
Diameter=Radius*2
17*2=34
C=34(π)
B. (π)(5²)
Plug in the numbers into the formula. Remember that half of the diameter is the radius.
C. (π)(4.5)
There are two possible formulas that could be used to calculate the circumference of a circle: πd and 2πr.
The expression above is simply multiplying the circle's radius times pi. Therefore, it is not a method that could be used to find the circumference of a circle.
D. (π)(6.5²)
Remember that the formula for calculating the area of a circle is πr².
Half of the diameter is 6.5 (13.5/2=6.5). 6.5 cm. is the radius. Now just plug the numbers into the formula.
(π)(6.5²)
Therefore, the last answer choice is the correct answer.
Answer:
27.385 cm longer would we expect Mike's arm span to be than George's.
Step-by-step explanation:
We have to find how many centimeters longer would we expect Mike's arm span to be than George's using the equation:
y= 4.5x + 0.977 x
where y= arm span
and x= height
Given:
Mike's height=x = 175 cm
so Mike's arm span= y= 4.5 x + 0.977 x
= 4.5* (175) + 0.977* (175)
= 787.5 + 170.975
= 958.475 cm
George's height = x = 170 cm
so George's arm span= y= 4.5 x + 0.977 x
= 4.5* (170) + 0.977* (170)
= 765 + 166.09
= 931.09 cm
Mike's arm span longer than George's = Mike's arm span - George's arm span
= 958.475 - 931.09
= 27.385 cm.
5x - 11 < -11
5x < 0
x < 0
4x + 2 > 14
4x > 12
x > 3
x<0 or x > 3
First we will change them on the same denominator which will be 12. If we do something to the denominator we must do the same to the numerator so :
For 1/3 we get 4/12 because (1/3)*4 = 4/12
And for 2/3 we get 8/12 because (2/3)*4 = 8/12
So 1/3 is the smaller fraction, 7/12 is in the middle and 2/3 is the bigger fraction.
