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Citrus2011 [14]
3 years ago
15

How long does it take an SR-71 Blackbird to make a surveillance run of 10,026 miles if it travels at an average of 2,228 mph

Mathematics
1 answer:
g100num [7]3 years ago
4 0
This is simple division:
t = \frac{10026}{2228}

So, plug it into your calculator and you get:
t = 4.5

Your answer's that it takes 4.5 hrs for the surveillance run.
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Fill in the blank.<br> (5x)2<br> a0x2
Yuki888 [10]

Answer:a_0=25

Step-by-step explanation:

It is given that, (5x)^2=a_0x^2

We need to find the value of a_0

As (5x)^2=a_0x^2

Solving LHS

25x^2=a_0x^2

Now comparing the coefficients of x^2

In LHS the coefficient of x^2 is 25

In RHS the coefficient of x^2 is a_0

It implies that, a_0=25

So, the value of a_0 is 25.

5 0
3 years ago
Name the property. 7+(11+10)=(7+11)+10
VikaD [51]

Answer:

associative

Step-by-step explanation:

u switched parentheses

5 0
3 years ago
G(x) = -0.5x^2 + 4x – 2
-BARSIC- [3]

Answer:

Step-by-step explanation:

What is the question?

g(x) = -0.5x² + 4x - 2 is a down-opening parabola. Do you need to know how to put it in vertex form?

vertex (4,6)

focus (4,5.5)

5 0
2 years ago
Optimization problem: what are the dimensions of the lightest open-top right circularcylindrical can that will hold a volume of
vivado [14]
So Volume of cylinder is pi*r^2*h = 1,000 

Then lightest one means you have the smallest surface area. Which is one base and then the area of the surface. SA = pi*r^2 + 2pi*r*h 

So now you have 2 equations, so: 

h = 1,000/(pi*r^2) 
So then SA = pi*r^2 + 2pi*r*(1,000/(pi*r^2) = pi*r^2 + 2,000/r 

Derivative of SA is then 2pi*r -2,000/r^2. Set to 0 

2pi*r-2,000/r^2 =0 --> 2pi*r^3 = 2,000 --> r^3 = 1,000/pi --> r = 10/pi^(1/3) 

Now go back to the volume function: pi*r^2*h =1,000 --> 1,000/(pi*100/pi^(2/3)) = h 
<span>h = 10 / pi^(1/3)</span>
3 0
3 years ago
Rewrite the following without an exponent. (9/5^-2)​
zvonat [6]

Answer:

225

Step-by-step explanation:

5^-2 can be rewritten as 1/25.

Then we can divide 1/25 by 9. 9/(1/25)= 225

6 0
3 years ago
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