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DerKrebs [107]
3 years ago
10

HELP THIS IS THE 5TH TIME I POSTED THIS BRUH

Mathematics
1 answer:
Delvig [45]3 years ago
4 0

Answer:

it's blurry all i see is pixels...

i'll help if you send me a picture...

Step-by-step explanation:

You might be interested in
In ∆ABC, point D is the centroid. If (AE) ̅=15, (BF) ̅=27, and (CD) ̅=8, find the following lengths
Anna71 [15]

Answer:

5,18,12 cms are the answer.

Step-by-step explanation:

Given is a triangle ABC.  Point D is the centroid.  

E,F and G are midpoints of CB, BA and AC respectively.

AE, BF and CG are medians of the triangle.

We know that centroid divides the median in the ratio 2:1

Using this we find that AD:DE = 2:1

Or AD+DE:DE = (2+1):1

AE:DE =3:1

15:DE = 3:1 . Hence DE =5 cm.

On the similar grounds we find that DF = 1/3 BF = 9

Hence BD = DF-BF = 27-9 =18 cm

and also

CG = 3/2 times CD = 12 cm.

7 0
3 years ago
Range, mode, MAD, median IQR, mean
Jlenok [28]

Answer:

range=8, mode=1  Median=3 mean=4

Step-by-step explanation:

range= subtract largest from smallest

mode= most frequent

median= middle in an ordered data set

Mean= add them all up and divide by how many you addded up

6 0
2 years ago
Read 2 more answers
Twice the difference of 3x and y increased by 5 times the sum of x and 2y
Phantasy [73]
The answer is 2(3x-y)+5(x+2y).
8 0
3 years ago
Reading proficiency: An educator wants to construct a 99.5% confidence interval for the proportion of elementary school children
Shkiper50 [21]

Answer:

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error of the interval is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In this problem, we have that:

p = 0.69

99.5% confidence level

So \alpha = 0.005, z is the value of Z that has a pvalue of 1 - \frac{0.005}{2} = 0.9975, so Z = 2.81.

Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?

This is n when M = 0.07. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.07 = 2.81\sqrt{\frac{0.69*0.31}{n}}

0.07\sqrt{n} = 1.2996

\sqrt{n} = \frac{1.2996}{0.07}

\sqrt{n} = 18.5658

(\sqrt{n})^{2} = (18.5658)^{2}

n = 345

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

4 0
3 years ago
57:12
suter [353]

Answer:

d

Step-by-step explanation:

6 0
2 years ago
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