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ss7ja [257]
3 years ago
5

If csc theta = -2.06, find sec(theta-pi/2)

Mathematics
1 answer:
Westkost [7]3 years ago
7 0

Answer:

a) sec (θ -π/2) =  co secθ

b) sin(\frac{\pi }{18} ) cos (\frac{\pi }{9})+ cos(\frac{\pi }{18} ) sin (\frac{\pi }{9} )=\frac{1}{2}

Step-by-step explanation:

a)

Given co sec θ = -2.06

sec (θ -π/2) = sec(π/2 -θ) = co secθ

b)

we will use formula

sin A cos B + Cos A sin B = sin(A+B)

Given sin(\frac{\pi }{18} ) cos (\frac{\pi }{9})+ cos(\frac{\pi }{18} ) sin (\frac{\pi }{9} )

                                                =  Sin(\frac{\pi }{18} +\frac{\pi }{9} )

                                                = sin(\frac{\pi+2\pi  }{18} ) = sin(\frac{3\pi }{18})

                                                = sin(\frac{\pi }{6})

                                               =  \frac{1}{2}

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