Answer:
the width is 9 23/30 feet ≈ 9.767 ft
Step-by-step explanation:
Let w represent the width of the train car. Then 6 times the width is 6w, and 8 ft less than that is (6w-8). We are told this amount is 50.6 feet, so we have ...
6w -8 = 50.6
6w = 58.6 . . . . . . . add 8; next divide by 6
58.6/6 = w = 586/60 = 293/30 = 9 23/30 . . . . feet
This is a repeating decimal: 9.766666...
The width of the train car is 9 23/30 ft, about 9.77 ft.
Answer:
The first plane is moving at 295 mph and the second plane is moving at 355mph.
Step-by-step explanation:
In order to find the speed of each plane we first need to know the relative speed between them, since they are flying in oposite directions their relative speed is the sum of their individual speeds. In this case the speed of the first plane will be "x" and the second plane will be "y". So we have:
x = y - 60
relative speed = x + y = (y - 60) + y = 2*y - 60
We can now apply the formula for average speed in order to solve for "y", we have:
average speed = distance/time
average speed = 1625/2.5 = 650 mph
In this case the average speed is equal to their relative speed, so we have:
2*y - 60 = 650
2*y = 650 + 60
2*y = 710
y = 710/2 = 355 mph
We can now solve for "x", we have:
x = 355 - 60 = 295 mph
The first plane is moving at 295 mph and the second plane is moving at 355mph.
Answer:
solution :
x = 4
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
5*(x-10)-(30-15*x)=0
Step by step solution :
Step 1 :
Equation at the end of step 1 :
5 • (x - 10) - (30 - 15x) = 0
Step 2 :
Step 3 :
Pulling out like terms :
3.1 Pull out like factors :
20x - 80 = 20 • (x - 4)
Equation at the end of step 3 :
20 • (x - 4) = 0
Step 4 :
Equations which are never true :
4.1 Solve : 20 = 0
Step-by-step explanation:
Standard form is ax+by=c
mnus 7y both sides
6x-7y=0
