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il63 [147K]
3 years ago
12

Expand And Simplify The Following:

Mathematics
2 answers:
Georgia [21]3 years ago
8 0
For all the questions, we will be using the FOIL pattern.
1. (x+3)(x-3)(3x+2)
(x^2-3x+3x-9)(3x+2)
(x^2-9)(3x+2)
3x^3+2x^2-27x-18
2. (2x+1)(x-2)(x+3)
(2x^2-4x+x-2)(x+3)
(2x^2-3x-2)(x+3)
2x^3+3x^2-11x-6
3. (x-3)(2x+1)(3x-2)
(2x^2+x-6x-3)(3x-2)
(2x^2-5x-3)(3x-2)
6x^3-19x^2+x+6
Hope this helped!
zloy xaker [14]3 years ago
6 0
I'm going to simp. them one by one
- <span>(x+3)(x-3)(3x+2)
- (x</span>²-9)(3x+2)
<span>- (x</span>³+2x²-27x-18)
<span>-x</span>³-2x²+27x+18
<span>
- (2x+1)(x-2)(x+3)
- (2x</span>²-4x+x-2)(x+3)
<span>- (2x</span>²-3x-2)(x+3)
<span>-  [x(2x</span>²-3x-2)+3(2x²-3x-2)]
<span>- (2x</span>³-3x²-2x)+(6x²-9x-6)
<span>- (2x</span>³+3x²-11x-6)    (combined like terms)
<span>-2x</span>³-3x²+11x+6<span>

- (x-3)(2x+1)(3x-2)
- (2x</span>²+x-6x-3)(3x-2)
- (2x²-5x-3)(3x-2)
- [3x(2x²-5x-3)-2(2x²-5x-3)]
- (6x³-15x²-9x)+(4x²+10x+6)
- (6x³-11x²+x+6)
-6x³+11x²-x-6

All you need w/ these problems is a bit of patience and to know the foil-ing process and distribution. :D
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Answer:

1191.4 ; 34.5

Step-by-step explanation:

Given the data:

29; 37; 38; 40; 58; 67; 68; 69; 76; 86; 87; 95; 96; 96; 99; 106; 112; 127; 145; 150

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Σ(X - m)² / (n - 1)

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n = sample size

The standard deviation equals, sqrt(variance )

Using a calculator:

The variance, σ² ;

Mean = Σx / n = 1681 / 20 = 84.05

(x -m)^2

[(29-84.05)^2 + (37-84.05)^2 + (38-84.05)^2 + (40-84.05)^2 + (58-84.05)^2 + (67-84.05)^2 + (68-84.05)^2 + (69-84.05)^2 + (76-84.05)^2 + (86-84.05)^2 + (87-84.05)^2 + (95-84.05)^2 + (96-84.05)^2 + (96-84.05)^2 + (99-84.05)^2 + (106-84.05)^2 + (112-84.05)^2 + (127-84.05)^2 + (145-84.05)^2 + (150-84.05)^2] / 19

22636.95 / 19

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Standard deviation = sqrt( Variance)

Standard deviation = sqrt(1191.4184)

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