<h3>Given:</h3><h3>Large cone:</h3>
<h3>Small cone:</h3>
<h3>Note that:</h3>
<h3>To find:</h3>
- The volume of the frustum of the given cone.
<h3>Solution:</h3>
- Frustum is a part of a cone formed by cutting off the top by a parallel plane.
![\large\boxed{Formula: V= \frac{1}{3}\pi{r}^{2}h}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7BFormula%3A%20V%3D%20%5Cfrac%7B1%7D%7B3%7D%5Cpi%7Br%7D%5E%7B2%7Dh%7D)
Let's solve!
First, let's find the volume of the smaller cone.
Substitute the values according to the
formula.
![V= \frac{1}{3}×\pi×{4}^{2}×10](https://tex.z-dn.net/?f=V%3D%20%5Cfrac%7B1%7D%7B3%7D%C3%97%5Cpi%C3%97%7B4%7D%5E%7B2%7D%C3%9710)
![V= 167.5516082 \: {cm}^{3}](https://tex.z-dn.net/?f=V%3D%20167.5516082%20%5C%3A%20%7Bcm%7D%5E%7B3%7D)
Now, we can round off to the nearest hundredth.
The value in the thousandths place is smaller than 5 so we won't have to round up.
![\boxed{V= 167.55 \: {cm}^{3}}](https://tex.z-dn.net/?f=%5Cboxed%7BV%3D%20167.55%20%5C%3A%20%7Bcm%7D%5E%7B3%7D%7D)
Next, let's find the volume of the bigger cone.
Substitute the values according to the formula.
![V= \frac{1}{3}×\pi×{8}^{2}×20](https://tex.z-dn.net/?f=V%3D%20%5Cfrac%7B1%7D%7B3%7D%C3%97%5Cpi%C3%97%7B8%7D%5E%7B2%7D%C3%9720)
![V= 1340.412866 \: {cm}^{3}](https://tex.z-dn.net/?f=V%3D%201340.412866%20%5C%3A%20%7Bcm%7D%5E%7B3%7D)
Now, we can round off to the nearest hundredth.
The value in thousandths place is smaller than 5 so we won't have to round up.
![\boxed{V=1340.41 \: {cm}^{3}}](https://tex.z-dn.net/?f=%5Cboxed%7BV%3D1340.41%20%5C%3A%20%7Bcm%7D%5E%7B3%7D%7D)
Now, we can find the volume of the frustum.
We'll have to minus the volume of the smaller cone from the bigger cone.
![V= 1340.41-167.55](https://tex.z-dn.net/?f=V%3D%201340.41-167.55)
![\large\boxed{V= 1172.86 \: {cm}^{3}}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7BV%3D%201172.86%20%5C%3A%20%7Bcm%7D%5E%7B3%7D%7D)
<u>Hence, the volume of the frustum is 1172.86 cubic centimeters.</u>
The isosceles trapezoid is part of an isosceles triangle with a 34 degree vertex angle. The measure of an acute base angle of the trapezoid is 73 degrees.
Answer:
EG = 13
Step-by-step explanation:
EG = EF + FG
EG = 4+ 9 = 13
A straight horizontal line where the y-intercept is -3
Answer:
b= -1/4
Step-by-step explanation:
I just get it on a work a day ago good luck