Answer:
Problem B: x = 12; m<EFG = 48
Problem C: m<G = 60; m<J = 120
Step-by-step explanation:
Problem B.
Angles EFG and IFH are vertical angles, so they are congruent.
m<EFG = m<IFH
4x = 48
x = 12
m<EFG = m<IFH = 48
Problem C.
One angle is marked a right angle, so its measure is 90 deg.
The next angle counterclockwise is marked 30 deg.
Add these two measures together, and you get 120 deg.
<J is vertical with the angle whose measure is 120 deg, so m<J = 120 deg.
Angles G and J from a linear pair, so they are supplementary, and the sum of their measures is 180 deg.
m<G = 180 - 120 = 60
Answer:
$2.50
Step-by-step explanation:
Shelley buys one pack of gum for $1
Price of gum: $1
Total amount of money spent: $1.00
Shelley buys another pack of gum for $0.50 more
1 + 0.50 = 1.5
Price of gum: $1.50
Total amount of money spent: $2.50
Circumference of a circle =2πr
6.28=2πr
3.14=πr
3.14/π=r
3.14/3.14=r
<h2>therefore,r=1</h2>
This is because of there different marketing statargies plus the reason behind this can be because they have high stock left and they want to clear that
Let α represent the acute angle between the horizontal and the straight line from the plane to the station. If the 4-mile measure is the straight-line distance from the plane to the station, then
sin(α) = 3/4
and
cos(α) = √(1 - (3/4)²) = (√7)/4
The distance from the station to the plane is increasing at a rate that is the plane's speed multiplied by the cosine of the angle α. Hence the plane–station distance is increasing at the rate of
(440 mph)×(√7)/4 ≈ 291 mph
