Since you know that a square has 4 equal sides then you know the small squares are 4cm on all sides and the big squares are 9cm on all sides.
If 2 and a partial sm sq are next to a 9cm sq then knowing 4*2=8 you can figure out that the other square is split as 1cm and 3cm(1+3=4), 3cm of which is lined up with the width (4cm)of another sm sq which would equal 7cm, these 2 sm sqs line up with the unknown sq whose sides would in turn also be 7cm.
A=l*w, 7*7=49
Answer:Area=49cm^2
$2.25+$2.25=$4.50 Twice a week
52 weeks in a year
$4.50x52 weeks = $234
Angle BAC is 75 because you subtract 27 from 102.
Answer:
The answer to the question is
The kinds of polygons that could be Diedre's quadrilateral are rectangle and square
Step-by-step explanation:
We note the conditions of the polygon as thus
Number of sides = 4, Which include trapezoid, square, rectangle
Size of angles = 90 ° which eliminates trapezoid
Sizes of opposite sides = Equal opposite sides, includes square and rectangle
With the above we conclude that the possible polygons in Diedre's quadrilateral are rectangle and square
