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Norma-Jean [14]
3 years ago
13

How do you solve this equation

Mathematics
1 answer:
algol [13]3 years ago
6 0
-2m,m= -3
-2m=-3-m
-2=-m
M=2
M=-3
I'm not sure but I found this
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Klio2033 [76]

Answer:

What do you need help with?

Step-by-step explanation:

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2 years ago
What are the zeros of f(x) = x2 - 12x + 36?
topjm [15]

Answer:

c. x = 6 only

Step-by-step explanation:

In order to calculate the zeros of f(x), we need to set it equal to zero and find the corresponding values of x.

x^{2}-12x+36=0

Using the midterm breaking, we can split -12x into two such terms whose sum will be -12x and product will be 36x². These two terms are -6x and -6x

So, the above expression can be written as:

x^2-6x-6x+36=0\\\\ x(x-6)-6(x-6)=0\\\\ (x-6)(x-6)=0\\\\ (x-6)^{2}=0\\\\ x-6=0\\\\ x=6

This means, the zero of f(x) occurs at x = 6 only.

8 0
3 years ago
Please help me find the value of x and show and explain work
riadik2000 [5.3K]
2x + 3 = 9      Move all terms not containing x to the right side of the equation.

2x = 6             Divide each term by 2 and simplify.

x=3
5 0
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Answer:

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Step-by-step explanation:

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A circle has a radius of 7.5 cm what is the diameter?
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Step-by-step explanation:

Radius times 2 is the diameter!

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