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ivolga24 [154]
3 years ago
12

What are the zeros of (x-2)(x^2-9)

Mathematics
2 answers:
Tatiana [17]3 years ago
7 0
                         (x - 2)(x² - 9) = 0
          (x - 2)(x² + 3x - 3x - 9) = 0
(x - 2)(x(x) + x(3) - 3(x) - 3(3)) = 0
                 (x - 2)(x - 3)(x + 3) = 0
x - 2 = 0  or  x - 3 = 0  or  x + 3 = 0
<u>  + 2 + 2</u>       <u>  + 3  + 3</u>       <u>   - 3  - 3</u>
     x = 2             x = 3             x = -3
SashulF [63]3 years ago
4 0
So because the factors of the equation are (x-2), (x+3) and (x-3), you set them equal to zero and you get x=2, -3, and 3
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