5Fe2(SO4)3 + K2SO4 + 2MnSO4 + 8H2O
In a reaction, molecular entity that is formed from the reactants. For example, consider this hypothetical stepwise reaction: A + B → C + D.
Answer:
c) 0.10M NaCl
Explanation:
<em>Options are:</em>
<em>a) 0.20M NaCl</em>
<em>b) Very acidic</em>
<em>c) 0.10M NaCl</em>
<em>d) 0.10M HCl + 0.20M NaOH</em>
<em>e) Slightly acidic.</em>
<em />
Based on the reaction:
NaOH + HCl → H₂O + NaCl
You can see than 1 mole of NaOH reacts per mole of HCl producing 1 mole of NaCl
Assuming 1L of 0.20M HCl reacts with 1L of NaOH, moles of both compounds are:
1L * 0.20mol/L = 0.20 moles reacts. That means moles of NaCl produced are 0.20moles in 2L. Molarity of NaCl is:
0.20mol / 2L = 0.10M NaCl
That means, right option is:
<h3>c) 0.10M NaCl</h3>
Answer:
pH = 0.81
Explanation:
HCl reacts with aniline, thus:
C₆H₅NH₂ + HCl → C₆H₅NH₃⁺ + Cl⁻
Moles of HCl are:
0.085L × (0.35mol HCl / L) = <em>0.02975mol HCl</em>
Moles of aniline are:
0.030L × (0.40mol HCl / L) = <em>0.012mol aniline</em>
Thus, after reaction, will remain:
0.02975mol - 0.012mol = <em>0.01775mol HCl</em>
Moles of HCl in solution are equal to moles of H⁺, thus, moles of H⁺ are: <em>0.01775mol H⁺</em>
As total volume is 85.0mL + 30.0mL = 115.0mL ≡ <em>0.115L</em>
0.01775mol / 0.115L = 0.1543M
pH of solution = -log[H⁺]
pH = -log 0.1543M
<em>pH = 0.81</em>
<em></em>
Answer:
Mg₃(PO₄)₂
Explanation:
This is a neutralization reaction between an acid and a base
The acid here is H₃PO₄
base is Mg(OH)₂
Every chemical reaction is made up of reactants on the left side and products formed on the right hand side of the expression;
3Mg(OH)₂
+ 2H₃PO₄
→ Mg₃(PO₄)₂ + 6H₂O
The reaction above is a double replacement reaction in which two ionic compounds gives an insoluble precipitate as a product when their ions displace one another in solution.
The solid formed is Mg₃(PO₄)₂
