3.8mL of 0.42 phosphoric acid is required.
Reaction
2H3PO4 + 3CaCL3 → Ca3(PO)4 + 6HCl
moles CaCl2 =0.16 mol/L x0.010 L = 0.0016 mol
moles of H3Po4
= 0.0016mol of CaCl2 x 2 mole of H3PO4/3mole of CaCl2
= 0.00106 mol
V of H3PO4 = 0.0016/0.42 = 0.0038L = 3.8mL
V of H3PO4=3.8mL
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Answer:
Coke.
Explanation:
The distillation of coal tar can obtain aromatic compounds like benzene and toluene, and also phenolic compounds like phenol. Hence, the only option here that cannot be obtained from the distillation of coal tar is coke.
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Answer:
Sample C is most likely the metal.
Explanation:
The Sample C is the metal, because the properties given in the sample c are all of the metal. As we know that the metals are the lustrous or the shiny elements. They are often good conductor of heat and also electricity. The metals possess high melting point. The density of the metals are heavy for their size. Metals can be easily hammered, and hence are malleable. They can easily be stretched into wires hence are ductile. They remains solid at room temperature but in case of mercury it remains as liquid. Metals are opaque object and cannot be see through it.
Answer is because
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