Answer:
illustrates ways things are similar and different
Explanation:
To be able to calculate the number of moles for this problem, for simplicity, we assume that it is an ideal gas. We use the equation PV = nRT. We do as follows:
PV = nRT
n = PV / RT
n = 1(100000) / 0.08206 (27 + 273.15)
n = 4060.04 mol
<h2>9. Given : P + O2 = P2O5</h2>
Balanced Chemical Equation: <u>4</u>P + <u>5</u>O2 = <u>2</u>P2O5
<u>Reactant Product</u>
P = (1) 4 | P = (2) 4
O = (2) 10 | O = (5) 10
Reaction Information
Phosphorus + Dioxygen = <u>Phosphorus Pentoxide</u>
Reaction Type: <u>Synthesis</u>
<h2>
10. Given: HCl + NaOH = NaCl + H2O </h2>
<u>Reactant Product</u>
H = 2 | H = 2
Cl = 1 | Cl = 1
Na = 1 | Na = 1
O = 1 | O = 1
<h3>
Chemical Equation is already in balance.</h3>
Reaction Information<em>:</em><em> </em><em>Hydrogen Chloride </em>+ <em>Sodium Hydroxide</em> = <em>Sodium Chloride </em>+ <em>Water</em>
Reaction Type<u> </u><u>:</u><u> </u><u>Double Displacement (Acid-Base)</u>
<h3>For more info:</h3>
<u>How to balance chemical equation?</u>
brainly.com/question/15939935
Answer:
a) pH will be 12.398
b) pH will be 4.82.
Explanation:
a) The moles of NaOH added = molarity X volume (L) = 2 X 0.01 = 0.02 moles
The total volume after addition of pure water = 0.780+0.01 = 0.79 L
The new concentration of /NaOH will be:

the [OH⁻] = 0.025
pOH = -log [OH⁻] = 1.602
pH = 14 -pOH = 12.398
b) The buffer has butanoic acid and butanoate ion.
i) Before addition of NaOH the pH will be calculated using Henderson Hassalbalch's equation:
![pH=pKa+log\frac{[salt]}{[acid]}](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bacid%5D%7D)
pKa=
ii) on addition of base the pH will increase.
Answer:

2,2,1 being the coefficients
Explanation:
These type of question rely on the person answering the question knowing the formula of hydrogen peroxide. Hydrogen peroxide has a formula that is very similar to that of water except it has a two after the O, which makes it very easy to remember.