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Sergio [31]
3 years ago
5

Simplify (3x2 - 5x + 3) + (-3x2 + 5x - 3).

Mathematics
2 answers:
Mars2501 [29]3 years ago
6 0

Answer:

0

Step-by-step explanation:

3x2 - 3x2 = 0

-5x + 5x = 0

3 - 3 = 0

zepelin [54]3 years ago
4 0

Answer:

(9 -5x) + (-9 +5x)

Step-by-step explanation:

-Three times two is six plus three is nine

-Negative three times two is negative six minus three which is negative nine

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In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. Of the students who have a dog as a pet also have cat as a pet.
Travka [436]

Answer:

This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:

"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"

Where X must be a positive number smaller than one, now we can solve it:

we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:

N = 45*(4/5) = 36

And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:

M = 36*X

now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")

M = 36*(1/2) = 18

So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.

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