1a) f(x) = I x+2 I. This is a piece-wise graph ( V form)
x = 0 →f(x) =2 (intercept y-axis)
x = -2→f(x) = 0 (intercept x-axis)
x = -3→f(x) = 1 (don't forget this is in absolute numbers)
x = -4→f(x) = 2 (don't forget this is in absolute numbers)
Now you can graph the V graph
1b) Translation: x to shift (-3) units and y remains the same, then
f(x-3) = I x - 3 + 2 I = I x-1 I
the V graph will shift one unit to the right, keeping the same y. Proof:
f(x) = I x-1 I . Intercept x-axis when I x-1 I = 0, so x= 1
Answer is a to the question
Step-by-step explanation:
(x + y , x - y) = (4 , 2)
x+y=4 ------(1)
x-y=2 ------(2)
_____ (adding two equation)
2x=6
x=3
From equation 1
3+y=4
y=1
If im right 60-8-8-8-8-8-8-8=4 so i think ur answer is 4
