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larisa86 [58]
3 years ago
13

1 × 6,391 _____ 0.1 × 6,391 ____ 0.01 × 6,391 _____

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
5 0

1.= 6,391  

2.=6,3910

3. = 6,39100

All you do is add the 0s at the end


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Suppose you borrow money for 6 months. If the interest rate is compounded monthly, the formula
Alinara [238K]

Answer:

$1045.85.

Step-by-step explanation:

A=p(1+r/12)^6

Here  r = 0.09, P = $1000 so

Amount of money needed to pay off the loan =

1000(1 + 0.09/12)^6

= $1045.85.

6 0
3 years ago
Please answer both questions and show all work with explanations :) thank you soo much...
torisob [31]

Answer:

1) 109 cm

2) 120 in²

Step-by-step explanation:

A rectangle is a quadrilateral with opposite sides the same length and four (4) right angles. The diagonal, together with two adjacent sides, forms a right triangle. The relationship between side lengths and the diagonal length is given by the Pythagorean theorem. If sides are "a" and "b" and the diagonal is "c", that theorem tells you ...

... c² = a² + b²

1) c² = (60 cm)² + (91 cm)² = 11881 cm²

... c = √11881 cm = 109 cm

2) The perimeter is double the sum of adjacent side lengths, so ...

... 2(a+b) = 46 in

... a + b = 23 in . . . . . divide by 2

The Pythagorean theorem tells you

... a² + b² = (17 in)²

Squaring the equation from the perimeter relation gives ...

... (a + b)² = (23 in)² = a² + 2ab + b²

Subtracting a² + b², we have

... (a² +2ab +b²) - (a² + b²) = (23 in)² -(17 in)²

... 2ab = (529 -289) in² = 240 in² . . . . . simplify

... 240 in²/2 = ab = 120 in² . . . . . area is the product of length and width

_____

We could solve the two equations for a and b to find that there are two possible solutions: (a, b) = (8, 15) or (15, 8). Either way, ab = 8·15 = 120.

7 0
3 years ago
Find the vertical and horizontal asymptote if they exist
tresset_1 [31]

Hello!

Vertical asymptotes are determined by setting the denominator of a rational function to zero and then by solving for x.

Horizontal asymptotes are determined by:

1. If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.

2. If the degree of the numerator = degree of denominator, then y = leading coefficient of numerator / leading coefficient of denominator is the horizontal asymptote.

3. If degree of numerator > degree of denominator, then there is an oblique asymptote, but no horizontal asymptote.

To find the vertical asymptote:

2x² - 10 = 0

2(x² - 5) = 0

(x - √5)(x + √5) = 0

x = √5 and x = -√5

Graphing the equation, we realize that x = -√5 is not a vertical asymptote, so therefore, the only vertical asymptote is x = √5.

To find the horizontal asymptote:

If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.

Therefore, the horizontal asymptote of this function is y = 0.

Short answer: Vertical asymptote: x = √5 and horizontal asymptote: y = 0

7 0
3 years ago
PLEASE HELP<br> Find the slope of any line parallel to the line through ( – 4, – 1) and ( – 6,0).
Rzqust [24]

Answer:

m= -1/2

Step-by-step explanation:

Parallel lines have the same slope, so find the slope between the 2 points.

0 - ( -1 ) / -6 - ( -4) = 1/-2

6 0
3 years ago
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Suppose a normal distribution has a mean of 48 and a standard deviation of 2. What is the probability that a data value is betwe
worty [1.4K]

Answer:

c 16.0%

Step-by-step explanation:

8 0
3 years ago
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