Answer:
The surface area of the pyramid is 466,137 squared cubits
Step-by-step explanation:
This is simply asking us to find the surface area of the square based pyramid with the given dimensions.
The first thing we need to know is the principle for finding the surface area of such pyramidal shapes. To get the surface area of a pyramid, we will have to add the base area to the area of the side faces ( lateral area)
The base area of the square based pyramid, will be the same as the area of a square which is = 453 cubits X 453 cubits =
The lateral area has already been given to us as 260,928 squared cubits.
The surface area of the pyramid is 260,928 + 205209 = 466137 squared cubits
Hence, the surface area of the pyramid is 466137 squared cubits
Answer:18
Step-by-step explanation:
C) 18 is the correct answer.
2m/3 +5=17
or,2m/3 =17-5
or,2m/3 =12.
Now doing criss cross multiplication,
or,3×12=2m×1
or,36=2m
m=18
If you found my answer useful then please mark me brainliest.
Answer:
C.)
275/9
Step-by-step explanation:
I think its C.)
Answer:
Step-by-step explanation:
Represent the width by W. Then, "The length of a rectangular field is 7 m less than 4 times the width" expressed symbolically is
L = 4W - 7 (dimensions in meters)
Recall that the perimeter formula in this case is P = 2L + 2W, and recognize that the perimeter value is 136 m. After substituting 4W - 7 for L, we get:
136 m = 2(4W - 7) + 2W, or
136 = 8W - 14 + 2W, or
150 = 10W These three equations are equivalent mathematical statements.
150 = 10W reduces to W = 15 (meters).
Part A: the independent variable is W, the width of the field.
Part B: The mathematical statement is 136 m = 2(4W - 7) + 2W, which after algebraic manipulation becomes 150 = 10W.
Part C: The above equation can be solved for W: W = 15 meters. This is the value of the independent variable.
Answer:
I think so b is the option
