<img src="https://tex.z-dn.net/?f=6%5Cfrac%7B1%7D%7B5%7D%20%2B8%5Cfrac%7B4%7D%7B5%7D" id="TexFormula1" title="6\frac{1}{5} +8\fr

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Rzqust [24]

3 years ago

ac{4}{5}" alt="6\frac{1}{5} +8\frac{4}{5}" align="absmiddle" class="latex-formula">
PLEASE SHOW WORK THANKS

Mathematics

2 answers:

Allushta [10]3 years ago

4 0

6 + 8 = 14

1/5 + 4/5 = 5/5 or 1

14 + 1 = 15

Cerrena [4.2K]3 years ago

3 0

61/5+84/5= the answer is 15

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sergij07 [2.7K]

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3 years ago

A researcher surveyed 150 high school students and found that 68% played a musical insturment. What would be a reasonable range

maria [59]

Answer:

The reasonable range for the population mean is (61%, 75%).

Step-by-step explanation:

The interval estimate of a population parameter is an interval of values that consist of the values within which the true value of the parameter lies with a certain probability.

The mean of the sampling distribution of sample proportion is, $\hat p$ .

One of the best interval estimate of population proportion is the 95% confidence interval for proportion,

$CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

Given:

n = 150

$\hat p$ = 0.68

The critical value of <em>z</em> for 95% confidence level is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Compute the 95% confidence interval for proportion as follows:

$CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=0.68\pm1.96\sqrt{\frac{0.68(1-0.68)}{150}}\\\\=0.68\pm 0.0747\\\\=(0.6053, 0.7547)\\\\\approx (0.61, 0.75)$

Thus, the reasonable range for the population mean is (61%, 75%).

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3 years ago

Can anyone help me with this im having some difficulty

Whitepunk [10]

Answer:

option C

Step-by-step explanation:

$(a+b)(a+b) = a^2 + 2ab + b^2$

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