Question

A girl and a boy are riding on a merry-go-round that is turning at a constant rate. The girl is near the outer edge, and the boy is closer to the center. Who has greater angular displacement after the merry-go-round makes one full rotation? Both the girl and the boy have zero angular displacement. Both the girl and the boy have the same nonzero angular displacement. The boy has greater angular displacement. The girl has greater angular displacement.

Answer 1

Answer:same

Explanation:

Both girl and boy will have the same angular displacement

As angular displacement is given by

$\theta =\omega _0t+\frac{1}{2}\alpha t^2$

where , $\theta =$angular displacement

$\omega _0=$initial angular velocity

$\alpha =$angular acceleration

from above expression we can see that it is independent of radius of object so angular velocity and angular acceleration will be same thus they have same angular displacement